Edexcel A-Level Chemistry 9CH0
Atomic Structure and the Periodic Table
Bonding and Structure
Inorganic Chemistry and the Periodic Table
Formulae, Equations and Amounts of Substance
Organic Chemistry I
Modern Analytical Techniques I
Energetics I
Kinetics I
Equilibrium I
Acid-Base Equilibria
Energetics II
Redox II
Transition Metals
Kinetics II
Organic Chemistry II
Organic Chemistry III
Formulae, Equations and Amounts of Substance
Percentage yield, atom economy and acid reactions
- 3 things to know
- Papers 1, 2 and 3
Overview
Percentage yield and theoretical yield, atom economy and why a high value is desirable, displacement reactions, the products of acids with metals, carbonates, metal oxides and alkalis, precipitation reactions, and hazard, risk and laboratory precautions.
What you need to know
Answer each one before you reveal it.
State the formula for percentage yield.
Calculate the percentage yield when actual yield = 17.4 g, theoretical yield = 20.7 g.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the formula for percentage yield.
Model answer
Percentage yield = (actual yield / theoretical yield) × 100%
- 2
Calculate the percentage yield when actual yield = 17.4 g, theoretical yield = 20.7 g.
Model answer
Percentage yield = (17.4 ÷ 20.7) × 100 = 84.1 %.
- 3
Define theoretical yield.
Model answer
Theoretical yield is the maximum mass of product that could be formed from the given amounts of reactants, assuming complete reaction.
- 4
State the formula for atom economy.
Model answer
Atom economy = (molar mass of desired product / sum of molar masses of all products) × 100%
- 5
Calculate the atom economy when molar mass of desired product = 374.6 g mol⁻¹, sum of molar masses of all products = 595.6 g mol⁻¹.
Model answer
Atom economy = (374.6 ÷ 595.6) × 100 = 62.9 %.
- 6
Why is a high atom economy desirable in a chemical reaction?
Model answer
A high atom economy means a greater proportion of reactant atoms end up in the desired product, making the reaction more efficient and sustainable.
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