CCEA A-Level Biology 1010
Biological Molecules
Enzymes
Viruses and Cell Structure
Cell Physiology and Transport
Continuity of Cells
Tissues and Organs
Exchange Surfaces and Gas Exchange
Transport in Plants
The Circulatory System in Mammals
Adaptation and Biodiversity
Human Impact on Biodiversity
Homeostasis and Excretion
Immunity
Co-Ordination and Control
Populations and Communities
Ecological Energetics and Nutrient Cycling
Respiration
Photosynthesis
DNA as the Genetic Code
Gene Technology
Genes and Patterns of Inheritance
Population Genetics and Evolution
Evolutionary Trends in Plants
Genes and Patterns of Inheritance
The chi-squared test
- 3 things to know
- Unit A2 2
Overview
The chi-squared formula, expected numbers and degrees of freedom, null hypotheses, and worked tests of monohybrid and dihybrid ratios read against the critical value at p = 0.05.
What you need to know
Answer each one before you reveal it.
Why is the chi-squared test unreliable when expected numbers are very small?
A cross gives 290 tall and 110 dwarf where 3:1 is expected. Is the difference significant?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is the chi-squared test used for in genetics?
Model answer
To find whether the difference between the observed numbers of offspring in each class and the numbers expected from a ratio is significant or due to chance.
- 2
State the formula for chi-squared and how its degrees of freedom are found.
Model answer
χ² = Σ(O − E)²/E, where O is observed and E is expected; the degrees of freedom are the number of classes minus one.
- 3
State a null hypothesis for a chi-squared test on a monohybrid cross.
Model answer
There is no significant difference between the observed numbers and those expected from a 3:1 ratio, so any difference is due to chance.
- 4
A monohybrid cross gives 140 tall and 60 dwarf plants. Test the fit to a 3:1 ratio (critical value 3.84 at p = 0.05).
Model answer
Expected values are 150 and 50. χ² = 100/150 + 100/50 = 0.67 + 2.00 = 2.67, which is below 3.84 at one degree of freedom, so the difference is not significant and the null hypothesis is accepted.
- 5
A dihybrid cross of 160 offspring gives 95, 28, 27 and 10. Test the fit to 9:3:3:1 (critical value 7.82).
Model answer
Expected values are 90, 30, 30 and 10. χ² = 25/90 + 4/30 + 9/30 + 0 = 0.71, below 7.82 at three degrees of freedom, so the results fit a 9:3:3:1 ratio.
- 6
What does it mean if the calculated chi-squared value exceeds the critical value at p = 0.05?
Model answer
The probability that the difference arose by chance is less than 5%, so the difference is significant and the null hypothesis is rejected, for example because genes are linked.
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