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Aldehydes and Ketones

Racemic mixtures from nucleophilic addition

  • 3 things to know
  • Unit A2 1

Overview

Shape of the carbonyl group before a nucleophile attacks it, effect of a racemic mixture on plane polarised light and why methanal cannot give a chiral product with hydrogen cyanide.

What you need to know

Answer each one before you reveal it.

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Key term

Describe the shape of the carbonyl group before a nucleophile attacks it.

Key term

Explain why a nucleophile can attack a carbonyl carbon from either side.

Key term

Describe what happens to the shape at the carbon atom once the nucleophile has added.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Describe the shape of the carbonyl group before a nucleophile attacks it.

    Model answer

    The carbonyl carbon is trigonal planar, so the carbon, the oxygen and the two attached groups all lie in the same plane.

  2. 2

    Explain why a nucleophile can attack a carbonyl carbon from either side.

    Model answer

    The carbonyl group is planar and neither face is shielded, so a cyanide ion approaching from above the plane is as likely as one approaching from below.

  3. 3

    Describe what happens to the shape at the carbon atom once the nucleophile has added.

    Model answer

    The carbon becomes tetrahedral, since it now has four groups attached and the double bond has gone.

  4. 4

    Explain why a racemic mixture is produced when hydrogen cyanide reacts with ethanal.

    Model answer

    The product carbon carries four different groups and attack occurs equally often from each face of the planar carbonyl group, so the two enantiomers are formed in equal amounts.

  5. 5

    Identify the chiral centre in 2-hydroxypropanenitrile.

    Model answer

    The second carbon is chiral because it carries a hydrogen atom, a hydroxyl group, a methyl group and a nitrile group.

  6. 6

    State the effect of a racemic mixture on plane polarised light.

    Model answer

    It has no effect, because the equal and opposite rotations of the two enantiomers cancel out.

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