levo

Aromatic Chemistry

The stability of benzene compared with alkenes

  • 3 things to know
  • Unit A2 1

Overview

Standard enthalpy of hydrogenation of cyclohexene, measured enthalpy of hydrogenation of benzene and why benzene undergoes substitution rather than addition.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Key term

Compare the π electron density in benzene with that in an alkene.

Key term

State the standard enthalpy of hydrogenation of cyclohexene.

Numbers

Calculate the enthalpy of hydrogenation predicted for a benzene ring with three separate double bonds.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the standard enthalpy of hydrogenation of cyclohexene.

    Model answer

    The enthalpy of hydrogenation of cyclohexene is −120 kJ mol⁻¹.

  2. 2

    Calculate the enthalpy of hydrogenation predicted for a benzene ring with three separate double bonds.

    Model answer

    Three times the value for one double bond gives 3 × −120 = −360 kJ mol⁻¹.

  3. 3

    State the measured enthalpy of hydrogenation of benzene.

    Model answer

    The measured value is −208 kJ mol⁻¹.

  4. 4

    Calculate the delocalisation energy of benzene from those two values.

    Model answer

    The difference between the expected −360 kJ mol⁻¹ and the actual −208 kJ mol⁻¹ is 152 kJ mol⁻¹, so benzene is 152 kJ mol⁻¹ more stable than the model with three separate double bonds.

  5. 5

    Explain what the difference between the predicted and measured enthalpies of hydrogenation shows about benzene.

    Model answer

    Less energy is released than predicted, so benzene starts from a lower energy than the model structure and is therefore more stable than three isolated double bonds would be.

  6. 6

    Explain why benzene undergoes substitution rather than addition.

    Model answer

    Addition would use up the delocalised π electrons and destroy the ring system, losing the extra stability, whereas substitution leaves the delocalised ring intact.

Other ways to work this

The same content, four other ways.

What is inside Levo

Six ways to work the same material.

1Closed book
2Open book
3Closed book

The 3-step method, run for you

Answer cold, learn it, then prove it stuck. Levo tracks the jump between your first attempt and your last.

Formulae, Equations and Amounts of Substance
Atomic Structure
Bonding
Intermolecular Forces and Structure

Cram a whole paper in one sitting

Sort every topic into what you know and what you do not, then drill only the weak ones.

Yellow to .
brownbluegreen

Blank Blitz makes facts automatic

Rapid timed gap-fills on the terms and numbers you need to recall without thinking.

AThe reactants total 159.6 + 84.0 = 243.6.
BThe two moles of iron have a mass of 111.6.
CThe atom economy is 45.8%.

Build It gets the exam shape right

Assemble a full-mark answer from its marking points, in the order an examiner wants them.

There are 1000 cm³ in one dm³.
TrueFalse

Test It catches misconceptions

Spot the fault in a statement. The traps are the mistakes students actually make.

721941163128510

Brain Breaks between sessions

Short focus games to reset attention, so the next set lands better than the last.

Every question in Aromatic Chemistry, on a schedule.

Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.

Or £46 a year, about £3.83 a month. Cancel anytime.