levo

Electrode Potentials

Electrode potentials and reactivity

  • 3 things to know
  • Unit A2 2

Overview

Recall questions on how the electrochemical series relates to the reactivity series, comparing reducing strength from potentials, predicting displacement reactions and halogen oxidations, corrosion in electrochemical terms, sacrificial protection and galvanising, why some metals occur native, and why a reactive metal must be extracted by electrolysis.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Key term

How does the electrochemical series relate to the reactivity series of metals?

Key term

Which metal is the stronger reducing agent, magnesium at −2.37 V or iron at −0.44 V?

Key term

Predict whether magnesium will displace copper from copper sulfate solution.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    How does the electrochemical series relate to the reactivity series of metals?

    Model answer

    The metals with the most negative standard electrode potentials are the most reactive, because they lose electrons most readily.

  2. 2

    Which metal is the stronger reducing agent, magnesium at −2.37 V or iron at −0.44 V?

    Model answer

    Magnesium, because its more negative potential means it releases electrons more readily.

  3. 3

    Predict whether magnesium will displace copper from copper sulfate solution.

    Model answer

    Copper at +0.34 V minus magnesium at −2.37 V gives an emf of +2.71 V, so the displacement is feasible.

  4. 4

    Why does a displacement reaction happen at all, in electrode potential terms?

    Model answer

    The metal with the more negative potential is oxidised and the ion of the metal with the more positive potential is reduced, which gives a positive emf.

  5. 5

    Why is a halogen higher in the group a stronger oxidising agent?

    Model answer

    Its standard electrode potential is more positive, so it accepts electrons more readily than a halogen below it.

  6. 6

    Predict whether chlorine at +1.36 V will oxidise bromide ions, given Br₂/Br⁻ is +1.09 V.

    Model answer

    The emf is 1.36 minus 1.09, which is +0.27 V, so chlorine does displace bromine from a bromide solution.

Other ways to work this

The same content, four other ways.

What is inside Levo

Six ways to work the same material.

1Closed book
2Open book
3Closed book

The 3-step method, run for you

Answer cold, learn it, then prove it stuck. Levo tracks the jump between your first attempt and your last.

Formulae, Equations and Amounts of Substance
Atomic Structure
Bonding
Intermolecular Forces and Structure

Cram a whole paper in one sitting

Sort every topic into what you know and what you do not, then drill only the weak ones.

Yellow to .
brownbluegreen

Blank Blitz makes facts automatic

Rapid timed gap-fills on the terms and numbers you need to recall without thinking.

AThe reactants total 159.6 + 84.0 = 243.6.
BThe two moles of iron have a mass of 111.6.
CThe atom economy is 45.8%.

Build It gets the exam shape right

Assemble a full-mark answer from its marking points, in the order an examiner wants them.

There are 1000 cm³ in one dm³.
TrueFalse

Test It catches misconceptions

Spot the fault in a statement. The traps are the mistakes students actually make.

721941163128510

Brain Breaks between sessions

Short focus games to reset attention, so the next set lands better than the last.

Every question in Electrode Potentials, on a schedule.

Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.

Or £46 a year, about £3.83 a month. Cancel anytime.