CCEA A-Level Chemistry 1110
Formulae, Equations and Amounts of Substance
Atomic Structure
Bonding
Intermolecular Forces and Structure
Shapes of Molecules and Ions
Redox
The Halogens
Acid-Base Titrations
Qualitative Tests
Formulae and Amounts of a Substance
Nomenclature and Isomerism in Organic Chemistry
Alkanes
Alkenes
Halogenoalkanes
Alcohols
Infrared Spectroscopy
Energetics
Kinetics
Equilibrium
Group II Elements and Their Compounds
Lattice Enthalpy, Entropy and Free Energy
Rates of Reaction
Equilibrium and Acid-Base Equilibria
Isomerism
Aldehydes and Ketones
Carboxylic Acids
Derivatives of Carboxylic Acids
Aromatic Chemistry
Spectroscopy and Chromatography
Volumetric Analysis
Transition Metals
Electrode Potentials
Amines
Amides and Polymers
Amino Acids and Proteins
Equilibrium and Acid-Base Equilibria
Calculating the pH of a buffer solution
- 3 things to know
- Unit A2 1
Overview
Recall questions on the buffer expression and why it uses the ratio of acid to salt, calculating the pH of ethanoic acid and propanoic acid buffers, working from an acid partly neutralised by alkali, why pH equals pKa at half-neutralisation, finding the ratio needed for a target pH, and showing the effect of added alkali.
What you need to know
Answer each one before you reveal it.
Explain why the pH at half-neutralisation of a weak acid equals its pKa.
A buffer of pH 4.58 rises only to pH 4.76 when a quantity of alkali is added. Explain how this demonstrates buffering
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the expression used to find the hydrogen ion concentration of an acidic buffer.
Model answer
The hydrogen ion concentration equals Ka multiplied by the concentration of the acid divided by the concentration of its salt.
- 2
Explain why the buffer expression uses the ratio of acid to salt rather than their absolute concentrations.
Model answer
Both concentrations appear in the same volume of solution, so the volume cancels and only their ratio, or equivalently the ratio of moles, determines the pH.
- 3
Calculate the pH of a buffer containing 0.100 mol dm⁻³ ethanoic acid and 0.100 mol dm⁻³ sodium ethanoate, given Ka = 1.74 × 10⁻⁵ mol dm⁻³.
Model answer
The ratio is one, so the hydrogen ion concentration equals Ka at 1.74 × 10⁻⁵ mol dm⁻³ and the pH is 4.76.
- 4
Calculate the pH of a buffer containing 0.200 mol dm⁻³ ethanoic acid and 0.100 mol dm⁻³ sodium ethanoate, given Ka = 1.74 × 10⁻⁵ mol dm⁻³.
Model answer
The hydrogen ion concentration is 1.74 × 10⁻⁵ × 2 = 3.48 × 10⁻⁵ mol dm⁻³, giving a pH of 4.46.
- 5
50.0 cm³ of 0.200 mol dm⁻³ ethanoic acid is mixed with 20.0 cm³ of 0.200 mol dm⁻³ sodium hydroxide. Calculate the moles of ethanoic acid remaining.
Model answer
There are 0.0100 mol of acid and 0.00400 mol of alkali, so 0.00600 mol of ethanoic acid remains unreacted.
- 6
For that mixture of 0.00600 mol ethanoic acid and 0.00400 mol ethanoate, calculate the pH given Ka = 1.74 × 10⁻⁵ mol dm⁻³.
Model answer
The hydrogen ion concentration is 1.74 × 10⁻⁵ × (0.00600 ÷ 0.00400) = 2.61 × 10⁻⁵ mol dm⁻³, giving a pH of 4.58.
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