CCEA A-Level Chemistry 1110
Formulae, Equations and Amounts of Substance
Atomic Structure
Bonding
Intermolecular Forces and Structure
Shapes of Molecules and Ions
Redox
The Halogens
Acid-Base Titrations
Qualitative Tests
Formulae and Amounts of a Substance
Nomenclature and Isomerism in Organic Chemistry
Alkanes
Alkenes
Halogenoalkanes
Alcohols
Infrared Spectroscopy
Energetics
Kinetics
Equilibrium
Group II Elements and Their Compounds
Lattice Enthalpy, Entropy and Free Energy
Rates of Reaction
Equilibrium and Acid-Base Equilibria
Isomerism
Aldehydes and Ketones
Carboxylic Acids
Derivatives of Carboxylic Acids
Aromatic Chemistry
Spectroscopy and Chromatography
Volumetric Analysis
Transition Metals
Electrode Potentials
Amines
Amides and Polymers
Amino Acids and Proteins
Formulae, Equations and Amounts of Substance
The mole, molar mass and Avogadro's constant
- 3 things to know
- Unit AS 1
Overview
Avogadro's constant and state its value and molar mass and give its unit.
What you need to know
Answer each one before you reveal it.
Define the mole.
Define Avogadro's constant and state its value.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Define the mole.
Model answer
The mole is the amount of substance that contains exactly 6.02214076 × 10²³ particles, the Avogadro constant. This is very nearly the number of atoms in exactly 12 g of carbon-12, which was the definition before 2019.
- 2
Define Avogadro's constant and state its value.
Model answer
Avogadro's constant is the number of particles in one mole of a substance, and its value is 6.02 × 10²³ mol⁻¹.
- 3
Define molar mass and give its unit.
Model answer
Molar mass is the mass of one mole of a substance, measured in g mol⁻¹.
- 4
How is the number of moles in a pure sample calculated from its mass?
Model answer
The number of moles equals the mass in grams divided by the molar mass in g mol⁻¹.
- 5
Calculate the amount in moles in 4.40 g of carbon dioxide.
Model answer
The molar mass of CO₂ is 44.0 g mol⁻¹, so the amount is 4.40 ÷ 44.0 = 0.100 mol.
- 6
Calculate the mass of 0.250 mol of sodium carbonate, Na₂CO₃.
Model answer
The molar mass is 106.0 g mol⁻¹, so the mass is 0.250 × 106.0 = 26.5 g.
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