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Amines

Physical properties of amines

  • 3 things to know
  • Unit A2 2

Overview

Recall questions on hydrogen bonding in a primary amine and its effect on boiling point, comparisons with propane and with an alcohol of similar mass, why a tertiary amine boils lower, why the smaller amines dissolve in water and why solubility falls with chain length, the fishy smell and why lemon juice removes it, and why the solution is alkaline.

What you need to know

Answer each one before you reveal it.

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Key term

Why does an amine boil lower than an alcohol of similar mass?

Key term

Why does the solubility of amines in water fall as the carbon chain lengthens?

Key term

Why does adding lemon juice reduce the smell of fish?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Why can a primary amine form hydrogen bonds?

    Model answer

    Its nitrogen carries a lone pair and its N−H bonds are polar, so it has both a donor and an acceptor.

  2. 2

    How does hydrogen bonding affect the boiling point of an amine?

    Model answer

    It raises the boiling point above that of an alkane of similar relative molecular mass, because more energy is needed to separate the molecules.

  3. 3

    Compare the boiling points of ethylamine and propane.

    Model answer

    Ethylamine boils considerably higher, even though the two have almost the same relative molecular mass, because propane has only van der Waals forces.

  4. 4

    Why does an amine boil lower than an alcohol of similar mass?

    Model answer

    Nitrogen is less electronegative than oxygen, so the hydrogen bonds between amine molecules are weaker.

  5. 5

    Why does a tertiary amine boil lower than a primary amine of the same mass?

    Model answer

    It has no N−H bond, so its molecules cannot hydrogen bond to each other, though they can still accept a hydrogen bond from water.

  6. 6

    Why are the smaller amines soluble in water?

    Model answer

    They form hydrogen bonds with water molecules, which releases enough energy to separate both sets of molecules.

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