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Transition Metals

Vanadium and the interconversion of its oxidation states

  • 3 things to know
  • Unit A2 2

Overview

Recall questions on acidified ammonium metavanadate as the source of vanadium(V), the yellow to blue to green to violet sequence with zinc and the species and oxidation state behind each colour, the three half-equations and their potentials, why zinc reduces all the way, and choosing a reducing agent from a table of potentials.

What you need to know

Answer each one before you reveal it.

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Key term

What compound is used as the source of vanadium(V) in the laboratory?

Key term

What reagent is used to reduce vanadium(V) through its lower oxidation states?

Process

Give the sequence of colours observed as zinc reduces acidified ammonium metavanadate.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What compound is used as the source of vanadium(V) in the laboratory?

    Model answer

    Ammonium metavanadate, acidified to give the yellow dioxovanadium(V) ion.

  2. 2

    Give the formula of the vanadium(V) species in acid solution.

    Model answer

    VO₂⁺.

  3. 3

    What reagent is used to reduce vanadium(V) through its lower oxidation states?

    Model answer

    Zinc metal, in the presence of acid.

  4. 4

    Give the sequence of colours observed as zinc reduces acidified ammonium metavanadate.

    Model answer

    Yellow to blue to green to violet.

  5. 5

    Name the species responsible for each of those colours.

    Model answer

    Yellow is VO₂⁺, blue is VO²⁺, green is V³⁺ and violet is V²⁺.

  6. 6

    Give the oxidation states corresponding to that sequence.

    Model answer

    Plus five, plus four, plus three and plus two.

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