CCEA A-Level Chemistry 1110
Formulae, Equations and Amounts of Substance
Atomic Structure
Bonding
Intermolecular Forces and Structure
Shapes of Molecules and Ions
Redox
The Halogens
Acid-Base Titrations
Qualitative Tests
Formulae and Amounts of a Substance
Nomenclature and Isomerism in Organic Chemistry
Alkanes
Alkenes
Halogenoalkanes
Alcohols
Infrared Spectroscopy
Energetics
Kinetics
Equilibrium
Group II Elements and Their Compounds
Lattice Enthalpy, Entropy and Free Energy
Rates of Reaction
Equilibrium and Acid-Base Equilibria
Isomerism
Aldehydes and Ketones
Carboxylic Acids
Derivatives of Carboxylic Acids
Aromatic Chemistry
Spectroscopy and Chromatography
Volumetric Analysis
Transition Metals
Electrode Potentials
Amines
Amides and Polymers
Amino Acids and Proteins
Formulae and Amounts of a Substance
Calculating formulae from composition data
- 3 things to know
- Unit AS 2
Overview
Recall questions on the method for an empirical formula from masses or percentages, why moles are found before the ratio is taken, dividing through by the smallest figure, handling a ratio ending in .5, and going on to a molecular formula from the relative molecular mass.
What you need to know
Answer each one before you reveal it.
A compound contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen by mass. Deduce its empirical formula.
A hydrocarbon is 85.7% carbon and 14.3% hydrogen by mass and has a relative molecular mass of 56.0. Deduce its molecular formula.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Describe the method for finding an empirical formula from percentage composition by mass.
Model answer
Divide each percentage by the relative atomic mass of that element, divide every answer by the smallest of them, then scale the results to the nearest whole numbers.
- 2
Why is each mole figure divided by the smallest one when finding an empirical formula?
Model answer
Dividing by the smallest figure sets the least abundant element to one and so gives the simplest ratio directly.
- 3
2.43 g of magnesium combines with 1.60 g of oxygen. Deduce the empirical formula of the oxide.
Model answer
The magnesium gives 2.43 divided by 24.3, which is 0.100 mol, and the oxygen gives 1.60 divided by 16.0, which is also 0.100 mol, so the empirical formula is MgO.
- 4
A compound contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen by mass. Deduce its empirical formula.
Model answer
The mole figures are 3.33, 6.7 and 3.33, which divide to a ratio of 1 : 2 : 1, so the empirical formula is CH₂O.
- 5
A compound of empirical formula CH₂O has a relative molecular mass of 180.0. Deduce its molecular formula.
Model answer
The empirical formula mass is 30.0 and 180.0 divided by 30.0 is 6, so the molecular formula is C₆H₁₂O₆.
- 6
A hydrocarbon is 85.7% carbon and 14.3% hydrogen by mass and has a relative molecular mass of 56.0. Deduce its molecular formula.
Model answer
The mole figures are 7.14 and 14.3, a ratio of 1 : 2, giving the empirical formula CH₂ of mass 14.0, and 56.0 divided by 14.0 is 4, so the molecular formula is C₄H₈.
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