CCEA A-Level Chemistry 1110
Formulae, Equations and Amounts of Substance
Atomic Structure
Bonding
Intermolecular Forces and Structure
Shapes of Molecules and Ions
Redox
The Halogens
Acid-Base Titrations
Qualitative Tests
Formulae and Amounts of a Substance
Nomenclature and Isomerism in Organic Chemistry
Alkanes
Alkenes
Halogenoalkanes
Alcohols
Infrared Spectroscopy
Energetics
Kinetics
Equilibrium
Group II Elements and Their Compounds
Lattice Enthalpy, Entropy and Free Energy
Rates of Reaction
Equilibrium and Acid-Base Equilibria
Isomerism
Aldehydes and Ketones
Carboxylic Acids
Derivatives of Carboxylic Acids
Aromatic Chemistry
Spectroscopy and Chromatography
Volumetric Analysis
Transition Metals
Electrode Potentials
Amines
Amides and Polymers
Amino Acids and Proteins
Lattice Enthalpy, Entropy and Free Energy
Free energy and the temperature of feasibility
- 3 things to know
- Unit A2 1
Overview
Condition on ΔG for a process to be feasible and what is true of ΔG for a system at equilibrium.
What you need to know
Answer each one before you reveal it.
State the condition on ΔG for a process to be feasible.
Give the units of ΔG and of T in the free energy equation.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the equation that relates free energy change to enthalpy and entropy changes.
Model answer
The relationship is ΔG = ΔH − TΔS, where T is the absolute temperature in kelvin.
- 2
State the condition on ΔG for a process to be feasible.
Model answer
A process is feasible when the free energy change is negative.
- 3
Give the units of ΔG and of T in the free energy equation.
Model answer
ΔG is in kJ mol⁻¹ and T is in kelvin.
- 4
For a reaction ΔH is −92 kJ mol⁻¹ and ΔS is −201 J K⁻¹ mol⁻¹. Calculate ΔG at 298 K.
Model answer
ΔG is −92 − 298(−0.201) = −92 + 59.9 = −32.1 kJ mol⁻¹.
- 5
The decomposition of calcium carbonate has ΔH = +178 kJ mol⁻¹ and ΔS = +161 J K⁻¹ mol⁻¹. Calculate ΔG at 298 K.
Model answer
ΔG is 178 − 298(0.161) = 178 − 48 = +130 kJ mol⁻¹.
- 6
Using ΔH = +178 kJ mol⁻¹ and ΔS = +161 J K⁻¹ mol⁻¹, calculate the minimum temperature at which calcium carbonate decomposes.
Model answer
Setting ΔG to zero gives T = 178 000 ÷ 161 = 1106 K.
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