CCEA A-Level Chemistry 1110
Formulae, Equations and Amounts of Substance
Atomic Structure
Bonding
Intermolecular Forces and Structure
Shapes of Molecules and Ions
Redox
The Halogens
Acid-Base Titrations
Qualitative Tests
Formulae and Amounts of a Substance
Nomenclature and Isomerism in Organic Chemistry
Alkanes
Alkenes
Halogenoalkanes
Alcohols
Infrared Spectroscopy
Energetics
Kinetics
Equilibrium
Group II Elements and Their Compounds
Lattice Enthalpy, Entropy and Free Energy
Rates of Reaction
Equilibrium and Acid-Base Equilibria
Isomerism
Aldehydes and Ketones
Carboxylic Acids
Derivatives of Carboxylic Acids
Aromatic Chemistry
Spectroscopy and Chromatography
Volumetric Analysis
Transition Metals
Electrode Potentials
Amines
Amides and Polymers
Amino Acids and Proteins
Lattice Enthalpy, Entropy and Free Energy
Standard entropy change calculations
- 3 things to know
- Unit A2 1
Overview
Recall questions on the products-minus-reactants expression and why coefficients are applied, worked calculations for the decomposition of calcium carbonate, the synthesis of ammonia, boiling water and the reduction of carbon dioxide, converting to kJ K⁻¹ mol⁻¹, why an element's standard entropy is not zero, and why boiling gives a far larger change than melting.
What you need to know
Answer each one before you reveal it.
Why must each standard entropy be multiplied by the coefficient from the balanced equation?
Calculate ΔSӨ for CaCO₃(s) → CaO(s) + CO₂(g), given standard entropies of 93, 40 and 214 J K⁻¹ mol⁻¹ respectively.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the expression used to calculate a standard entropy change for a reaction.
Model answer
The standard entropy change equals the total standard entropy of the products minus the total standard entropy of the reactants.
- 2
Why must each standard entropy be multiplied by the coefficient from the balanced equation?
Model answer
Standard entropies are quoted per mole, so a species present as two moles contributes twice its molar value.
- 3
Calculate ΔSӨ for CaCO₃(s) → CaO(s) + CO₂(g), given standard entropies of 93, 40 and 214 J K⁻¹ mol⁻¹ respectively.
Model answer
The products total 40 + 214 = 254 J K⁻¹ mol⁻¹, so ΔSӨ is 254 − 93 = +161 J K⁻¹ mol⁻¹.
- 4
Calculate ΔSӨ for N₂(g) + 3H₂(g) → 2NH₃(g), given standard entropies of 192, 131 and 192 J K⁻¹ mol⁻¹ respectively.
Model answer
The products total 2(192) = 384 J K⁻¹ mol⁻¹ and the reactants 192 + 3(131) = 585 J K⁻¹ mol⁻¹, so ΔSӨ is 384 − 585 = −201 J K⁻¹ mol⁻¹.
- 5
Calculate ΔSӨ for H₂O(l) → H₂O(g), given standard entropies of 70 and 189 J K⁻¹ mol⁻¹.
Model answer
The entropy change is 189 − 70 = +119 J K⁻¹ mol⁻¹.
- 6
Calculate ΔSӨ for 2H₂(g) + O₂(g) → 2H₂O(l), given standard entropies of 131, 205 and 70 J K⁻¹ mol⁻¹ respectively.
Model answer
The products total 2(70) = 140 J K⁻¹ mol⁻¹ and the reactants 2(131) + 205 = 467 J K⁻¹ mol⁻¹, so ΔSӨ is 140 − 467 = −327 J K⁻¹ mol⁻¹.
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