OCR A-Level Physics B H557
Planning
Implementing
Analysis
Evaluation
Practical Skills
Use of Apparatus and Techniques
Fundamental Data Analysis
Imaging and Signalling
Sensing
Mechanical Properties of Materials
Waves and Quantum Behaviour
Space, Time and Motion
Creating Models
Out Into Space
Our Place in the Universe
Matter: Very Simple
Matter: Hot or Cold
Electromagnetism
Charge and Field
Probing Deep Into Matter
Ionising Radiation and Risk
Charge and Field
Radial fields and the inverse square law
- 3 things to know
- Components 01, 02 and 03
Overview
Recall questions on F = kqQ/r² and E = kQ/r², the electric force constant and the permittivity of free space ε₀, force and field calculations, attraction and repulsion, tripling the separation, field patterns around a negative charge and a pair of opposite charges, charged spheres as point charges, zero field inside a hollow conductor, surface charge, and sharp points.
What you need to know
Answer each one before you reveal it.
Why does excess charge on a solid conductor sit on its outer surface?
State the value of the electric force constant k and the relationship that defines it.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Write the equation for the electric force between two point charges.
Model answer
The force is F = kqQ/r², where q and Q are the charges, r is their separation and k is the electric force constant.
- 2
State the value of the electric force constant k and the relationship that defines it.
Model answer
The electric force constant is k = 1/(4πε₀), and its value is 8.98 × 10⁹ N m² C⁻².
- 3
State the value and unit of the permittivity of free space.
Model answer
The permittivity of free space is ε₀ = 8.85 × 10⁻¹² C² N⁻¹ m⁻², which may also be written as F m⁻¹.
- 4
Write the equation for the electric field strength at a distance r from a point charge Q.
Model answer
The field strength is E = kQ/r², directed radially away from Q if Q is positive.
- 5
Calculate the force between charges of 2.0 × 10⁻⁸ C and 3.0 × 10⁻⁹ C placed 0.050 m apart in air.
Model answer
F = kqQ/r² = 8.98 × 10⁹ × 2.0 × 10⁻⁸ × 3.0 × 10⁻⁹ ÷ (0.050)² = 2.2 × 10⁻⁴ N.
- 6
Calculate the electric field strength 0.050 m from a point charge of 2.0 × 10⁻⁸ C.
Model answer
E = kQ/r² = 8.98 × 10⁹ × 2.0 × 10⁻⁸ ÷ (0.050)² = 7.2 × 10⁴ V m⁻¹.
Other ways to work this
The same content, four other ways.
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