OCR A-Level Physics B H557
Planning
Implementing
Analysis
Evaluation
Practical Skills
Use of Apparatus and Techniques
Fundamental Data Analysis
Imaging and Signalling
Sensing
Mechanical Properties of Materials
Waves and Quantum Behaviour
Space, Time and Motion
Creating Models
Out Into Space
Our Place in the Universe
Matter: Very Simple
Matter: Hot or Cold
Electromagnetism
Charge and Field
Probing Deep Into Matter
Ionising Radiation and Risk
Creating Models
Energy stored on a capacitor
- 3 things to know
- Components 01, 02 and 03
Overview
Recall questions on why the stored energy is not simply charge times voltage, the equivalent expressions, area under a charge–voltage graph, delivering large power briefly, and where a battery's energy goes.
What you need to know
Answer each one before you reveal it.
Why is the energy stored on a capacitor ½QV rather than QV?
What are the three equivalent expressions for the energy stored on a capacitor?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Why is the energy stored on a capacitor ½QV rather than QV?
Model answer
The potential difference rises from zero to V as charge builds up, so the average potential difference through which the charge is moved is only ½V.
- 2
What are the three equivalent expressions for the energy stored on a capacitor?
Model answer
The energy is E = ½QV, E = ½CV² and E = ½Q²/C.
- 3
How is the energy stored on a capacitor found from a graph of charge against potential difference?
Model answer
It is the area under the Q–V graph, which for a straight line through the origin is the triangle of area ½QV.
- 4
A 470 μF capacitor is charged to 12 V. How much energy is stored?
Model answer
E = ½CV² = 0.5 × 470 × 10⁻⁶ × 12² = 3.4 × 10⁻² J.
- 5
A capacitor stores 6.0 mC at 9.0 V. Calculate the energy stored.
Model answer
E = ½QV = 0.5 × 6.0 × 10⁻³ × 9.0 = 2.7 × 10⁻² J.
- 6
What happens to the energy stored on a capacitor if the potential difference across it is doubled?
Model answer
The energy becomes four times larger, because E = ½CV² makes the energy proportional to the square of the potential difference.
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