OCR A-Level Physics B H557
Planning
Implementing
Analysis
Evaluation
Practical Skills
Use of Apparatus and Techniques
Fundamental Data Analysis
Imaging and Signalling
Sensing
Mechanical Properties of Materials
Waves and Quantum Behaviour
Space, Time and Motion
Creating Models
Out Into Space
Our Place in the Universe
Matter: Very Simple
Matter: Hot or Cold
Electromagnetism
Charge and Field
Probing Deep Into Matter
Ionising Radiation and Risk
Creating Models
Energy in simple harmonic motion
- 2 things to know
- Components 01, 02 and 03
Overview
Recall questions on energy stored ½kx² and Hooke's law F = kx, total energy ½mv² + ½kx², how kinetic and potential energy interchange, where kinetic energy is zero or greatest, calculating stored and total energy, maximum speed and kinetic energy at a displacement, energy in proportion to amplitude squared, and energy–displacement and energy–time graphs.
What you need to know
Answer each one before you reveal it.
State Hooke's law in the form used for an oscillating spring.
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is the expression for the energy stored in a spring obeying Hooke's law?
Model answer
The stored energy is E = ½kx², where x is the extension or compression.
- 2
State Hooke's law in the form used for an oscillating spring.
Model answer
The force is F = kx, where k is the stiffness and x the extension or compression.
- 3
What is the total energy of a mass–spring oscillator at any instant?
Model answer
The total energy is E = ½mv² + ½kx².
- 4
How do kinetic and potential energy vary during one oscillation?
Model answer
They interchange twice per cycle, the potential energy being greatest at maximum displacement and the kinetic energy greatest at the equilibrium position.
- 5
Where in the cycle is the kinetic energy of an undamped oscillator zero?
Model answer
At the extremes of the motion, where the oscillator is momentarily at rest.
- 6
A spring of stiffness 20 N m⁻¹ is stretched by 0.10 m. How much energy is stored?
Model answer
E = ½kx² = 0.5 × 20 × 0.010 = 0.10 J.
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