OCR A-Level Physics B H557
Planning
Implementing
Analysis
Evaluation
Practical Skills
Use of Apparatus and Techniques
Fundamental Data Analysis
Imaging and Signalling
Sensing
Mechanical Properties of Materials
Waves and Quantum Behaviour
Space, Time and Motion
Creating Models
Out Into Space
Our Place in the Universe
Matter: Very Simple
Matter: Hot or Cold
Electromagnetism
Charge and Field
Probing Deep Into Matter
Ionising Radiation and Risk
Space, Time and Motion
Conservation of momentum and collisions
- 3 things to know
- Components 01, 02 and 03
Overview
Recall questions on the conservation of momentum and why it follows from Newton's third law, the condition for it, trolleys sticking together and the kinetic energy lost, elastic and inelastic collisions, trolleys pushed apart by a spring, signs for direction, head-on collisions, gun and rifle recoil, air track tests, and the Earth's unnoticed momentum change.
What you need to know
Answer each one before you reveal it.
State the principle of conservation of momentum.
Why does conservation of momentum follow from Newton's third law?
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the principle of conservation of momentum.
Model answer
The total momentum of a system stays constant provided that no resultant external force acts on it.
- 2
Why does conservation of momentum follow from Newton's third law?
Model answer
The forces two colliding bodies exert on each other are equal and opposite and act for the same time, so the impulses are equal and opposite and the momentum changes cancel.
- 3
What condition must a system satisfy if its momentum is to be conserved?
Model answer
No resultant external force may act on it, so it must be isolated from outside influences such as friction.
- 4
A 2.0 kg trolley moving at 3.0 m s⁻¹ collides with a stationary 1.0 kg trolley and the two move off together. What is their common velocity?
Model answer
The total momentum of 6.0 kg m s⁻¹ is shared by 3.0 kg, so the common velocity is 2.0 m s⁻¹.
- 5
A 2.0 kg trolley at 3.0 m s⁻¹ sticks to a stationary 1.0 kg trolley and they move off at 2.0 m s⁻¹. What is the kinetic energy lost?
Model answer
Before the collision the kinetic energy is ½ × 2.0 × 3.0² = 9.0 J and afterwards it is ½ × 3.0 × 2.0² = 6.0 J, so 3.0 J is lost.
- 6
What distinguishes an elastic collision from an inelastic one?
Model answer
Kinetic energy is conserved in an elastic collision but not in an inelastic one, although momentum is conserved in both.
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