OCR A-Level Physics B H557
Planning
Implementing
Analysis
Evaluation
Practical Skills
Use of Apparatus and Techniques
Fundamental Data Analysis
Imaging and Signalling
Sensing
Mechanical Properties of Materials
Waves and Quantum Behaviour
Space, Time and Motion
Creating Models
Out Into Space
Our Place in the Universe
Matter: Very Simple
Matter: Hot or Cold
Electromagnetism
Charge and Field
Probing Deep Into Matter
Ionising Radiation and Risk
Out Into Space
Gravitational force and the radial field
- 3 things to know
- Components 01, 02 and 03
Overview
Recall questions on F = −GMm/r² and its minus sign, the gravitational constant G, the inverse square law, treating planets as point masses, satellite and sphere force calculations, doubling separation, why everyday attraction is unnoticeable, Newton's third law pairs, radial field lines, a larger planet's surface force, and gravity against the strong nuclear force.
What you need to know
Answer each one before you reveal it.
Why does the radial component of the gravitational force carry a minus sign?
State the value and unit of the universal gravitational constant.
Questions from this subtopic
Each one with the model answer underneath.
- 1
What equation gives the gravitational force between two point masses?
Model answer
The radial component of the force is F = −GMm/r², where r is the separation of their centres.
- 2
Why does the radial component of the gravitational force carry a minus sign?
Model answer
The force is attractive, so it acts in the opposite direction to increasing r.
- 3
State the value and unit of the universal gravitational constant.
Model answer
G is 6.67 × 10⁻¹¹ N m² kg⁻².
- 4
What does it mean to call gravitation an inverse square law?
Model answer
The magnitude of the force falls in proportion to 1/r², so tripling the separation reduces the force to a ninth.
- 5
How is a spherical planet treated when the force on an object outside it is calculated?
Model answer
Its whole mass is modelled as a point mass concentrated at its centre.
- 6
A 1500 kg satellite orbits 4.2 × 10⁷ m from the centre of an Earth of mass 5.97 × 10²⁴ kg. What gravitational force acts on it?
Model answer
F = GMm/r² = 6.67 × 10⁻¹¹ × 5.97 × 10²⁴ × 1500 / (4.2 × 10⁷)² = 3.4 × 10² N.
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