OCR A-Level Physics B H557
Planning
Implementing
Analysis
Evaluation
Practical Skills
Use of Apparatus and Techniques
Fundamental Data Analysis
Imaging and Signalling
Sensing
Mechanical Properties of Materials
Waves and Quantum Behaviour
Space, Time and Motion
Creating Models
Out Into Space
Our Place in the Universe
Matter: Very Simple
Matter: Hot or Cold
Electromagnetism
Charge and Field
Probing Deep Into Matter
Ionising Radiation and Risk
Probing Deep Into Matter
Discrete energy levels in atoms
- 3 things to know
- Components 01, 02 and 03
Overview
Recall questions on energy levels and the evidence of line spectra, ΔE = hf, frequency and wavelength calculations for a transition, absorption against emission spectra, electron collisions as evidence, electrons below the excitation energy, ionisation energy, negative energy values, ground and excited states, excitation against ionisation, and exciting an atom with a 10.4 V electron.
What you need to know
Answer each one before you reveal it.
Why is the emission spectrum of a gas a set of lines rather than a continuous band of colour?
Write the relationship between the energy difference of two levels and the frequency of the photon emitted.
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is meant by an energy level in an atom?
Model answer
An energy level is one of the set of definite energies that an electron in an atom is allowed to have, with no values in between.
- 2
How do line spectra provide evidence for discrete energy levels?
Model answer
A hot gas emits only certain sharply defined wavelengths, and each corresponds to a fixed photon energy, which can only happen if the electron energies before and after emission are themselves fixed.
- 3
Why is the emission spectrum of a gas a set of lines rather than a continuous band of colour?
Model answer
Only the differences between allowed energy levels are available as photon energies, so only a limited set of frequencies can be emitted.
- 4
Write the relationship between the energy difference of two levels and the frequency of the photon emitted.
Model answer
The photon energy equals the difference between the levels, so ΔE = hf.
- 5
Calculate the frequency of the photon emitted in a transition of energy 2.1 eV.
Model answer
The energy is 2.1 × 1.60 × 10⁻¹⁹ = 3.36 × 10⁻¹⁹ J, so f = ΔE/h = 3.36 × 10⁻¹⁹ ÷ 6.63 × 10⁻³⁴ = 5.1 × 10¹⁴ Hz.
- 6
Calculate the wavelength of a photon of frequency 5.1 × 10¹⁴ Hz.
Model answer
λ = c/f = 3.00 × 10⁸ ÷ 5.1 × 10¹⁴ = 5.9 × 10⁻⁷ m, which is 590 nm.
Other ways to work this
The same content, four other ways.
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