OCR A-Level Physics B H557
Planning
Implementing
Analysis
Evaluation
Practical Skills
Use of Apparatus and Techniques
Fundamental Data Analysis
Imaging and Signalling
Sensing
Mechanical Properties of Materials
Waves and Quantum Behaviour
Space, Time and Motion
Creating Models
Out Into Space
Our Place in the Universe
Matter: Very Simple
Matter: Hot or Cold
Electromagnetism
Charge and Field
Probing Deep Into Matter
Ionising Radiation and Risk
Out Into Space
Gravitational field strength
- 3 things to know
- Components 01, 02 and 03
Overview
Recall questions on the defining equation and unit, inverse-square variation around a planet, adding fields from two bodies and where they cancel, apparent weightlessness in orbit, and field-line spacing.
What you need to know
Answer each one before you reveal it.
Calculate the gravitational field strength at the surface of an Earth of mass 5.97 × 10²⁴ kg and radius 6.37 × 10⁶ m.
What is the field strength 6.37 × 10⁶ m above the surface of the Earth?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Define gravitational field strength.
Model answer
It is the gravitational force per unit mass acting on a small test mass placed at that point.
- 2
State the defining equation and unit of gravitational field strength.
Model answer
It is g = F/m, measured in N kg⁻¹.
- 3
What is the field strength at a distance r from a point mass M?
Model answer
The radial component is g = −GM/r².
- 4
Is gravitational field strength a scalar or a vector, and in which direction does it act?
Model answer
It is a vector, directed towards the mass producing the field.
- 5
Calculate the gravitational field strength at the surface of an Earth of mass 5.97 × 10²⁴ kg and radius 6.37 × 10⁶ m.
Model answer
g = GM/r² = 3.98 × 10¹⁴ / 4.06 × 10¹³ = 9.81 N kg⁻¹.
- 6
What is the field strength 6.37 × 10⁶ m above the surface of the Earth?
Model answer
The distance from the centre has doubled, so the field strength is a quarter of 9.81, that is 2.45 N kg⁻¹.
Other ways to work this
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