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Matter: Very Simple

Energy transfer and specific thermal capacity

  • 3 things to know
  • Components 01, 02 and 03

Overview

Recall questions on specific thermal capacity and its unit, ΔE = mcΔθ and why kelvin or degrees Celsius both work, heating water and aluminium, water against copper, coastal climates and coolants, what supplied energy does in a solid and a boiling liquid, estimating c from a kettle, why heating overestimates c, and temperature against internal energy.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Key term

In the relationship ΔE = mcΔθ, what does each quantity represent?

Key term

Why may the temperature change in ΔE = mcΔθ be given in kelvin or in degrees Celsius without altering the answer?

Numbers

An aluminium block of mass 1.0 kg and specific thermal capacity 900 J kg⁻¹ K⁻¹ absorbs 14 400 J. Calculate its temperature rise.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is meant by the specific thermal capacity of a substance?

    Model answer

    It is the energy needed to raise the temperature of one kilogram of the substance by one kelvin.

  2. 2

    Give the SI unit of specific thermal capacity.

    Model answer

    It is J kg⁻¹ K⁻¹.

  3. 3

    In the relationship ΔE = mcΔθ, what does each quantity represent?

    Model answer

    ΔE is the energy transferred, m the mass of the sample, c its specific thermal capacity and Δθ the temperature change.

  4. 4

    Why may the temperature change in ΔE = mcΔθ be given in kelvin or in degrees Celsius without altering the answer?

    Model answer

    A change of one kelvin is the same size as a change of one degree Celsius, so only the zero of the scale differs and a difference is unaffected.

  5. 5

    A mass of 0.50 kg of water is heated from 20 °C to 100 °C. Taking c as 4200 J kg⁻¹ K⁻¹, calculate the energy transferred.

    Model answer

    The energy transferred is 0.50 × 4200 × 80 = 1.7 × 10⁵ J.

  6. 6

    An aluminium block of mass 1.0 kg and specific thermal capacity 900 J kg⁻¹ K⁻¹ absorbs 14 400 J. Calculate its temperature rise.

    Model answer

    The rise is 14 400 ÷ (1.0 × 900) = 16 K.

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