OCR A-Level Physics B H557
Planning
Implementing
Analysis
Evaluation
Practical Skills
Use of Apparatus and Techniques
Fundamental Data Analysis
Imaging and Signalling
Sensing
Mechanical Properties of Materials
Waves and Quantum Behaviour
Space, Time and Motion
Creating Models
Out Into Space
Our Place in the Universe
Matter: Very Simple
Matter: Hot or Cold
Electromagnetism
Charge and Field
Probing Deep Into Matter
Ionising Radiation and Risk
Probing Deep Into Matter
Electron standing waves and the confined electron
- 3 things to know
- Components 01, 02 and 03
Overview
Recall questions on why confinement gives discrete energies, the allowed wavelengths and resulting momentum and energy, nodes in higher states, why an atom has a definite size, and the model's limits.
What you need to know
Answer each one before you reveal it.
Describe the simple model of an atom as an electron confined in a box.
Explain why confining an electron leads to a set of discrete energies.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Describe the simple model of an atom as an electron confined in a box.
Model answer
The electron is treated as a wave trapped between the walls of a small region, so only those wavelengths that fit a whole number of half-wavelengths into the box are allowed.
- 2
Explain why confining an electron leads to a set of discrete energies.
Model answer
Only certain standing wave patterns fit inside the confining region, and each allowed wavelength corresponds through p = h/λ to one particular momentum and therefore one particular energy.
- 3
Write the expression for the allowed wavelengths of an electron standing wave in a box of length L.
Model answer
The allowed wavelengths are λ = 2L/n, where n is a whole number counting the standing wave patterns.
- 4
Calculate the wavelength of the lowest-energy standing wave of an electron confined in a box of length 1.0 × 10⁻¹⁰ m.
Model answer
With n = 1, λ = 2L = 2 × 1.0 × 10⁻¹⁰ = 2.0 × 10⁻¹⁰ m.
- 5
Calculate the momentum of an electron whose de Broglie wavelength is 2.0 × 10⁻¹⁰ m.
Model answer
p = h/λ = 6.63 × 10⁻³⁴ ÷ 2.0 × 10⁻¹⁰ = 3.3 × 10⁻²⁴ N s.
- 6
Calculate the kinetic energy of an electron of momentum 3.3 × 10⁻²⁴ N s, and express it in electronvolts.
Model answer
Ek = p²/2m = (3.3 × 10⁻²⁴)² ÷ (2 × 9.11 × 10⁻³¹) = 6.0 × 10⁻¹⁸ J, which is about 38 eV.
Other ways to work this
The same content, four other ways.
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