OCR A-Level Physics B H557
Planning
Implementing
Analysis
Evaluation
Practical Skills
Use of Apparatus and Techniques
Fundamental Data Analysis
Imaging and Signalling
Sensing
Mechanical Properties of Materials
Waves and Quantum Behaviour
Space, Time and Motion
Creating Models
Out Into Space
Our Place in the Universe
Matter: Very Simple
Matter: Hot or Cold
Electromagnetism
Charge and Field
Probing Deep Into Matter
Ionising Radiation and Risk
Imaging and Signalling
Linear magnification
- 3 things to know
- Components 01, 02 and 03
Overview
Recall questions on relating magnification to object and image distances, why it has no unit, what a negative value means, image heights in cameras and projectors, and distant objects.
What you need to know
Answer each one before you reveal it.
Define linear magnification.
State the relationship between linear magnification and the object and image distances.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Define linear magnification.
Model answer
Linear magnification is the height of the image divided by the height of the object.
- 2
State the relationship between linear magnification and the object and image distances.
Model answer
m = v/u, the image distance divided by the object distance.
- 3
Why does linear magnification have no unit?
Model answer
It is the ratio of two lengths, so the units cancel.
- 4
What does a negative value of linear magnification tell you?
Model answer
It tells you the image is inverted relative to the object.
- 5
An object 0.30 m in front of a lens gives an image 0.60 m beyond it. Calculate the magnification and describe the image.
Model answer
m = 0.60/(−0.30) = −2.0, so the image is real, inverted and twice the height of the object.
- 6
An object 15 mm tall is imaged with a magnification of magnitude 3.0. State the height of the image.
Model answer
The image is 45 mm tall.
Other ways to work this
The same content, four other ways.
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