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Creating Models

Exponential curves on linear and logarithmic scales

  • 3 things to know
  • Components 01, 02 and 03

Overview

Recall questions on exponential decay on linear and logarithmic axes, why logarithms give a straight line, the intercept of ln V and gradient of ln N against time, spotting background counts, linearising capacitor charging, the constant-ratio property, why decay never reaches zero, gradient as current, finding the time constant, successive halvings, and logarithmic scales.

What you need to know

Answer each one before you reveal it.

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Key term

Why does taking logarithms turn an exponential into a straight line?

Key term

What does the intercept of a graph of ln V against t tell you for a discharging capacitor?

Key term

What does the gradient of a graph of ln N against t tell you for a decaying sample?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Describe the appearance of an exponential decay plotted on linear axes.

    Model answer

    It falls steeply at first, becomes progressively less steep and approaches the time axis asymptotically without crossing it.

  2. 2

    What shape does an exponential decay give when the quantity is shown on a logarithmic scale against time?

    Model answer

    It gives a straight line with a negative gradient.

  3. 3

    Why does taking logarithms turn an exponential into a straight line?

    Model answer

    Taking natural logarithms of x = x₀exp(−kt) gives ln x = ln x₀ − kt, which is linear in t.

  4. 4

    What does the intercept of a graph of ln V against t tell you for a discharging capacitor?

    Model answer

    The intercept on the vertical axis is ln V₀, so its exponential gives the initial potential difference.

  5. 5

    What does the gradient of a graph of ln N against t tell you for a decaying sample?

    Model answer

    The gradient is −λ, so its magnitude is the decay constant.

  6. 6

    Give one advantage of analysing decay data on a logarithmic scale.

    Model answer

    A straight line tests the exponential model directly and lets every data point contribute to a single gradient.

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