OCR A-Level Physics B H557
Planning
Implementing
Analysis
Evaluation
Practical Skills
Use of Apparatus and Techniques
Fundamental Data Analysis
Imaging and Signalling
Sensing
Mechanical Properties of Materials
Waves and Quantum Behaviour
Space, Time and Motion
Creating Models
Out Into Space
Our Place in the Universe
Matter: Very Simple
Matter: Hot or Cold
Electromagnetism
Charge and Field
Probing Deep Into Matter
Ionising Radiation and Risk
Creating Models
Period of a mass–spring system and a simple pendulum
- 2 things to know
- Components 01, 02 and 03
Overview
Recall questions on the two period equations and frequency, calculations for given masses, stiffnesses and lengths, why the bob's mass does not matter, timing from equilibrium, and squared-period graphs.
What you need to know
Answer each one before you reveal it.
What equation gives the period of a simple pendulum?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What equation gives the period of a mass oscillating on a spring?
Model answer
The period is T = 2π√(m/k).
- 2
What equation gives the period of a simple pendulum?
Model answer
The period is T = 2π√(L/g), where L is the length to the centre of the bob.
- 3
How are period and frequency related?
Model answer
The frequency is the reciprocal of the period, f = 1/T.
- 4
A 0.20 kg mass oscillates on a spring of stiffness 20 N m⁻¹. What is the period?
Model answer
T = 2π√(0.20/20) = 2π × 0.10 = 0.63 s.
- 5
A 0.50 kg mass hangs on a spring of stiffness 32 N m⁻¹. What is the frequency of oscillation?
Model answer
T = 2π√(0.50/32) = 0.79 s, so f = 1/T = 1.3 Hz.
- 6
Calculate the period of a simple pendulum of length 0.25 m.
Model answer
T = 2π√(0.25/9.81) = 1.0 s.
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