OCR A-Level Physics B H557
Planning
Implementing
Analysis
Evaluation
Practical Skills
Use of Apparatus and Techniques
Fundamental Data Analysis
Imaging and Signalling
Sensing
Mechanical Properties of Materials
Waves and Quantum Behaviour
Space, Time and Motion
Creating Models
Out Into Space
Our Place in the Universe
Matter: Very Simple
Matter: Hot or Cold
Electromagnetism
Charge and Field
Probing Deep Into Matter
Ionising Radiation and Risk
Sensing
Kirchhoff's laws and conservation in circuits
- 3 things to know
- Components 01, 02 and 03
Overview
Recall questions on Kirchhoff's first and second laws and the conservation of charge and energy they express, finding an unknown branch current and potential difference, why charge does not build up at a junction, signs around a loop, a cell with internal resistance, lamps in parallel, and why the laws hold in any network.
What you need to know
Answer each one before you reveal it.
State Kirchhoff's second law.
Currents of 2.0 A and 1.5 A enter a junction, and 0.80 A leaves along one branch. Calculate the current in the remaining branch.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State Kirchhoff's first law.
Model answer
The total current entering a junction is equal to the total current leaving it.
- 2
Which conservation principle does Kirchhoff's first law express?
Model answer
It expresses the conservation of electric charge.
- 3
State Kirchhoff's second law.
Model answer
Around any closed loop, the sum of the e.m.f.s equals the sum of the potential differences across the components.
- 4
Which conservation principle does Kirchhoff's second law express?
Model answer
It expresses the conservation of energy.
- 5
Currents of 2.0 A and 1.5 A enter a junction, and 0.80 A leaves along one branch. Calculate the current in the remaining branch.
Model answer
2.0 + 1.5 − 0.80 = 2.7 A leaves along the remaining branch.
- 6
Explain why charge does not build up at a junction in a circuit carrying a steady current.
Model answer
Charge is conserved and cannot accumulate in a conductor at a steady current, so it must leave the junction at the same rate as it arrives.
Other ways to work this
The same content, four other ways.
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