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Waves and Quantum Behaviour

Standing waves in air columns and the speed of sound

  • 3 things to know
  • Components 01, 02 and 03

Overview

Recall questions on how an air column resonates, where nodes and antinodes fall, using two resonance positions rather than one, oscilloscope frequency measurements, and a closed tube's resonance ratio.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Key term

How is an oscilloscope used to measure the frequency of a sound?

Key term

State the wavelength of the lowest resonant sound in a tube of length l closed at one end.

Key term

Why is the difference between two resonance positions used rather than the first resonance alone?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    How does a standing sound wave form in a tube closed at one end?

    Model answer

    Sound travelling down the tube reflects at the closed end and superposes with the incoming wave, producing a standing wave when the length of the air column matches a resonant condition.

  2. 2

    Is there a node or an antinode at the closed end of a resonance tube, and why?

    Model answer

    There is a displacement node at the closed end, because the air there cannot move along the tube.

  3. 3

    Is there a node or an antinode at the open end of a resonance tube?

    Model answer

    There is a displacement antinode close to the open end, where the air is free to move.

  4. 4

    State the wavelength of the lowest resonant sound in a tube of length l closed at one end.

    Model answer

    The wavelength is 4l, because the tube holds a quarter of a wavelength.

  5. 5

    The first resonance of a tube closed at one end occurs when the air column is 0.16 m long. What is the wavelength of the sound?

    Model answer

    The wavelength is 4 × 0.16 = 0.64 m.

  6. 6

    Successive resonances of a tube driven at 500 Hz occur at air-column lengths of 0.16 m and 0.48 m. What is the speed of sound in the air?

    Model answer

    The two lengths differ by half a wavelength, so λ = 2 × 0.32 = 0.64 m and v = fλ = 500 × 0.64 = 320 m s⁻¹.

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