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Creating Models

Modelling oscillations step by step

  • 2 things to know
  • Components 01, 02 and 03

Overview

Recall questions on setting up the calculation for a mass on a spring, the starting conditions needed, recalculating acceleration each step, errors from too large a step, energy checks, and damping.

What you need to know

Answer each one before you reveal it.

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Key term

How is a step-by-step model of a mass on a spring built?

Key term

A 0.50 kg mass on a spring of stiffness 8.0 N m⁻¹ is released from a displacement of 0.10 m. What is its initial acceleration?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    How is a step-by-step model of a mass on a spring built?

    Model answer

    From the present displacement the acceleration is found as −(k/m)x, the velocity is updated by aΔt, the displacement is updated by vΔt, and the cycle repeats.

  2. 2

    What equation of motion does a numerical model of a mass–spring oscillator solve?

    Model answer

    It solves d²x/dt² = −(k/m)x.

  3. 3

    A 0.50 kg mass on a spring of stiffness 8.0 N m⁻¹ is released from a displacement of 0.10 m. What is its initial acceleration?

    Model answer

    a = −(k/m)x = −(8.0/0.50) × 0.10 = −1.6 m s⁻², directed back towards equilibrium.

  4. 4

    An oscillator released from rest has an acceleration of −1.6 m s⁻². What is its velocity after one time step of 0.010 s?

    Model answer

    Δv = aΔt = −1.6 × 0.010 = −0.016 m s⁻¹, so the velocity is −0.016 m s⁻¹.

  5. 5

    A modelled oscillator at x = 0.100 m has velocity −0.016 m s⁻¹. What is its displacement after a further step of 0.010 s?

    Model answer

    Δx = vΔt = −0.016 × 0.010 = −1.6 × 10⁻⁴ m, so the displacement becomes 0.0998 m.

  6. 6

    Why must the acceleration be recalculated at every step of the model?

    Model answer

    The acceleration depends on the displacement, which changes continuously, so a fixed value would not describe the motion.

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