OCR A-Level Chemistry B H433
Development of Practical Skills in Chemistry
Elements of Life
Developing Fuels
Elements From the Sea
The Ozone Story
What's in a Medicine?
The Chemical Industry
Polymers and Life
Oceans
Developing Metals
Colour by Design
Chemical Literacy
Mathematical Skills in Chemistry
Chemical Literacy
Extracting and using data and information from a scientific text
- 4 things to know
- Component 02
Overview
Recall questions on converting the units quoted in an article, checking them before substituting, reading a table, and judging how many figures an answer deserves.
What you need to know
Answer each one before you reveal it.
Could a 7.0 mol dm⁻³ sodium chloride solution be made when the solubility is 36 g per 100 cm³ (Mᵣ 58.5), why must units from an article be checked, and how is the dependent-variable column of a table identified?
To how many figures should an answer from an article be quoted, how is kg per hour converted, and what does a 112% yield mean?
How many moles of water are there in 1.00 dm³, taking the density as 1.00 g cm⁻³?
Questions from this subtopic
Each one with the model answer underneath.
- 1
An article states that seawater contains 19.4 g dm⁻³ of chloride ions. What is this concentration in mol dm⁻³, given Aᵣ(Cl) = 35.5?
Model answer
The concentration is 19.4 ÷ 35.5 = 0.546 mol dm⁻³.
- 2
A passage gives the atmospheric carbon dioxide level as 420 ppm by volume. Express this as a percentage by volume.
Model answer
420 parts per million is (420 ÷ 10⁶) × 100 = 0.0420% by volume.
- 3
A report quotes an emission of 1.00 tonne of carbon dioxide. How many moles is this, given Mᵣ(CO₂) = 44.0?
Model answer
1.00 tonne is 1.00 × 10⁶ g, so the amount is 1.00 × 10⁶ ÷ 44.0 = 2.27 × 10⁴ mol.
- 4
A text gives the C–C bond enthalpy as 348 kJ mol⁻¹. Calculate the energy needed to break a single C–C bond, using the Avogadro constant 6.02 × 10²³ mol⁻¹.
Model answer
The energy is 348 000 ÷ (6.02 × 10²³) = 5.78 × 10⁻¹⁹ J per bond.
- 5
An article reports that a new catalyst raises the yield of a process from 42% to 68%. Calculate the increase as a percentage of the original yield.
Model answer
The increase is (68 − 42) ÷ 42 × 100 = 61.9% of the original yield.
- 6
An article states that the solubility of sodium chloride is 36 g per 100 cm³ of water at 25 °C. Could a 7.0 mol dm⁻³ solution be prepared at that temperature, given Mᵣ = 58.5?
Model answer
No, because 36 g per 100 cm³ is 360 g dm⁻³, which is 360 ÷ 58.5 = 6.15 mol dm⁻³, so 7.0 mol dm⁻³ exceeds the solubility.
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