OCR A-Level Chemistry B H433
Development of Practical Skills in Chemistry
Elements of Life
Developing Fuels
Elements From the Sea
The Ozone Story
What's in a Medicine?
The Chemical Industry
Polymers and Life
Oceans
Developing Metals
Colour by Design
Chemical Literacy
Mathematical Skills in Chemistry
Oceans
Calculating the entropy change of the system
- 3 things to know
- Components 01, 02 and 03
Overview
Recall questions on using standard entropies, multiplying by the stoichiometric numbers, and why elements do not have zero standard entropy.
What you need to know
Answer each one before you reveal it.
Why is the entropy change of the system for the vaporisation of water large and positive?
Why are standard entropies quoted at a stated temperature and pressure?
Questions from this subtopic
Each one with the model answer underneath.
- 1
How is the entropy change of the system calculated from standard entropy data?
Model answer
ΔsysS is the sum of the standard entropies of the products minus the sum of the standard entropies of the reactants.
- 2
Why must each standard entropy be multiplied by the number in front of the formula in the equation?
Model answer
Entropy is an extensive quantity, so two moles of a substance contribute twice the entropy of one mole.
- 3
What are the units of a standard entropy value?
Model answer
They are J K⁻¹ mol⁻¹.
- 4
Why are the standard entropies of elements not zero, unlike their standard enthalpies of formation?
Model answer
Entropy is measured from a genuine zero at absolute zero, so any substance above 0 K has a real positive entropy.
- 5
Using S(N₂) = 191.6, S(H₂) = 130.6 and S(NH₃) = 192.3 J K⁻¹ mol⁻¹, calculate ΔsysS for N₂(g) + 3H₂(g) → 2NH₃(g).
Model answer
ΔsysS = 2 × 192.3 − (191.6 + 3 × 130.6) = 384.6 − 583.4 = −199 J K⁻¹ mol⁻¹ to three significant figures.
- 6
Using S(CaCO₃) = 92.9, S(CaO) = 39.7 and S(CO₂) = 213.6 J K⁻¹ mol⁻¹, calculate ΔsysS for CaCO₃(s) → CaO(s) + CO₂(g).
Model answer
ΔsysS = (39.7 + 213.6) − 92.9 = +160.4 J K⁻¹ mol⁻¹.
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