OCR A-Level Chemistry B H433
Development of Practical Skills in Chemistry
Elements of Life
Developing Fuels
Elements From the Sea
The Ozone Story
What's in a Medicine?
The Chemical Industry
Polymers and Life
Oceans
Developing Metals
Colour by Design
Chemical Literacy
Mathematical Skills in Chemistry
Developing Metals
Balancing redox equations involving acid-base reactions
- 4 things to know
- Components 01, 02 and 03
Overview
Recall questions on the manganate(VII) and dichromate(VI) half-equations, why the electron counts are what they are, and combining halves into a full equation.
What you need to know
Answer each one before you reveal it.
How are the manganate(VII) and iron(II) half-equations combined, and what is the dichromate(VI) half-equation?
How do the charges balance in the dichromate(VI) half-equation, what is its full ionic equation with iron(II), and what is the half-equation for the oxidation of ethanedioate?
Write the full ionic equation for the oxidation of hydrogen peroxide by manganate(VII) in acid.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Which two species are used to balance a redox half-equation taking place in acidic solution?
Model answer
Hydrogen ions H⁺ and water molecules H₂O are used.
- 2
What two things must balance in a correctly written half-equation?
Model answer
Every type of atom must balance and the total electrical charge must be the same on both sides.
- 3
Outline the steps for constructing a half-equation for a species that contains oxygen.
Model answer
Balance the element that changes oxidation state, add H₂O to balance the oxygen, add H⁺ to balance the hydrogen, then add electrons until the charges match.
- 4
Write the half-equation for the reduction of manganate(VII) to manganese(II) in acid.
Model answer
The half-equation is MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O.
- 5
Show that the charges balance in the half-equation MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O.
Model answer
The left side is (−1) + (+8) + (−5) = +2 and the right side is +2, so the charges are equal.
- 6
Why are exactly five electrons needed in the manganate(VII) half-equation?
Model answer
Manganese falls from oxidation state +7 to +2, a change of five, so five electrons are gained.
Other ways to work this
The same content, four other ways.
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