OCR A-Level Chemistry B H433
Development of Practical Skills in Chemistry
Elements of Life
Developing Fuels
Elements From the Sea
The Ozone Story
What's in a Medicine?
The Chemical Industry
Polymers and Life
Oceans
Developing Metals
Colour by Design
Chemical Literacy
Mathematical Skills in Chemistry
The Chemical Industry
Chemical reactions in industrial processes
- 1 thing to know
- Components 01, 02 and 03
Overview
Recall questions on the stages of nitric and sulfuric acid manufacture, why oleum is made, and the green case for a carbonylation route.
What you need to know
Answer each one before you reveal it.
Questions from this subtopic
Each one with the model answer underneath.
- 1
When an unfamiliar industrial reaction scheme is presented to you, what general chemical principles let you interpret it?
Model answer
Oxidation states reveal redox changes, gas-mole counts predict the effect of pressure, and the sign of ΔH predicts the effect of temperature on the yield.
- 2
In one stage of nitric acid manufacture ammonia is oxidised: 4NH₃ + 5O₂ → 4NO + 6H₂O. Deduce the change in oxidation state of nitrogen.
Model answer
Nitrogen goes from −3 in ammonia to +2 in nitrogen monoxide, an increase of five.
- 3
That oxidation uses a platinum–rhodium gauze. What is the role of the gauze?
Model answer
It is a heterogeneous catalyst, and the gauze form gives a very large surface area for the gases to react on.
- 4
Nitrogen monoxide is then oxidised further: 2NO + O₂ → 2NO₂. Give the oxidation state of nitrogen in each oxide.
Model answer
Nitrogen is +2 in NO and +4 in NO₂.
- 5
In the final stage, 3NO₂ + H₂O → 2HNO₃ + NO. Explain why this is a disproportionation.
Model answer
Nitrogen at +4 is simultaneously oxidised to +5 in nitric acid and reduced to +2 in nitrogen monoxide.
- 6
Why is the nitrogen monoxide formed in that final stage not wasted?
Model answer
It is recycled back to be reoxidised to nitrogen dioxide, raising the overall conversion.
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