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The Chemical Industry

Half-lives

  • 4 things to know
  • Components 01, 02 and 03

Overview

Recall questions on which order has a constant half-life, how successive half-lives behave for each order, and k = ln 2 / t½.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Numbers

Which order has a half-life independent of concentration, how do successive half-lives show first-order kinetics, and how do they behave for zero order?

Numbers

How do successive half-lives behave for second order, and how are the half-life and the rate constant related for a first-order reaction?

Evaluation

What concentration remains 150 s after a first-order reaction starts at 0.80 mol dm⁻³ with t½ = 50 s, why should more than one half-life be measured, and how long until 87.5% of a first-order reactant with t½ = 4.0 min has gone?

Key term

What is the symbol used for half-life?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Define the half-life of a reaction.

    Model answer

    The half-life is the time taken for the concentration of a reactant to fall to half of its value at the start of that interval.

  2. 2

    What is the symbol used for half-life?

    Model answer

    The symbol is t½.

  3. 3

    Which order of reaction has a half-life that is independent of concentration?

    Model answer

    A first-order reaction has a constant half-life.

  4. 4

    How can successive half-lives be used as evidence for first-order kinetics?

    Model answer

    If each successive half-life read from a concentration–time graph is the same, the reaction is first order in that reactant.

  5. 5

    How do successive half-lives behave for a zero-order reaction?

    Model answer

    Each successive half-life is half as long as the one before, because the concentration falls at a constant rate.

  6. 6

    How do successive half-lives behave for a second-order reaction?

    Model answer

    Each successive half-life is twice as long as the one before.

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