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Developing Metals

Bidentate and multidentate ligands, and finding a complex's formula

  • 3 things to know
  • Components 01, 02 and 03

Overview

Recall questions on the ethanedioate ion and EDTA, how many bind to one metal ion, and deducing a formula from a mole ratio.

What you need to know

Answer each one before you reveal it.

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Numbers

How does the ethanedioate ion act as a bidentate ligand, and how many can surround one metal ion?

Numbers

What are the coordination number and ligand count of [Fe(C₂O₄)₃]³⁻, and what happens when excess ammonia is added to copper?

Numbers

Which atom of water donates the lone pair, what are the coordination number and shape when 1.00 × 10⁻³ mol of a metal ion combines with 3.00 × 10⁻³ mol of a bidentate ligand, and what is the coordination number with a hexadentate ligand in a 1:1 ratio?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is the formula of the ethanedioate ion?

    Model answer

    It is C₂O₄²⁻.

  2. 2

    Describe the structure of the ethanedioate ion.

    Model answer

    It consists of two carboxylate groups joined directly by a carbon–carbon bond, with an overall charge of 2−.

  3. 3

    Explain how the ethanedioate ion acts as a bidentate ligand.

    Model answer

    One oxygen atom in each of its two carboxylate groups donates a lone pair, so it forms two coordinate bonds to the same metal ion.

  4. 4

    How many ethanedioate ions can surround one metal ion in an octahedral complex?

    Model answer

    Three, because each supplies two coordinate bonds and six are needed.

  5. 5

    What is the formula of the complex formed between Fe³⁺ and three ethanedioate ions?

    Model answer

    It is [Fe(C₂O₄)₃]³⁻.

  6. 6

    Write the equation for the formation of that complex from the hexaaqua iron(III) ion.

    Model answer

    The equation is [Fe(H₂O)₆]³⁺ + 3C₂O₄²⁻ → [Fe(C₂O₄)₃]³⁻ + 6H₂O.

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A3 ⁴₂He → ¹²₆C.
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C¹⁶₈O + ⁴₂He → ²⁰₁₀Ne.

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