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Elements of Life

Shapes of molecules and ions

  • 3 things to know
  • Components 01, 02 and 03

Overview

Recall questions on electron pair repulsion, why lone pairs repel more, and the shapes and bond angles of the common molecules and ions.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Key term

Which repels more strongly, a lone pair or a bonding pair, how do the three types of electron-pair repulsion rank, and why is BeCl₂ linear?

Key term

What shape is PH₃, and what is its bond angle?

Key term

What shape is a hydrogen sulfide molecule, H₂S?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the electron pair repulsion principle.

    Model answer

    Pairs of electrons in the outer shell of a central atom repel one another, so they take up positions as far apart as possible.

  2. 2

    Which repels more strongly, a lone pair or a bonding pair, and why?

    Model answer

    A lone pair repels more strongly because it is attracted only by the one central nucleus, so it is held closer in and occupies more space than a bonding pair, which is pulled out between two nuclei.

  3. 3

    Which is the strongest and which the weakest of lone pair–lone pair, lone pair–bonding pair and bonding pair–bonding pair repulsion?

    Model answer

    Lone pair–lone pair repulsion is strongest, then lone pair–bonding pair, and bonding pair–bonding pair is weakest.

  4. 4

    Outline the steps you would use to predict the shape of a molecule.

    Model answer

    Draw a ‘dot-and-cross’ diagram, count the bonding pairs and lone pairs around the central atom, arrange all of them as far apart as possible, then close the angles slightly for each lone pair and name the shape from the positions of the atoms only.

  5. 5

    What is the shape and bond angle of BeCl₂?

    Model answer

    It is linear with a bond angle of 180°, because beryllium has only two bonding pairs and no lone pairs.

  6. 6

    What is the shape and bond angle of BF₃?

    Model answer

    It is trigonal planar with bond angles of 120°, because boron has three bonding pairs and no lone pairs.

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A acid is formed.
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A3 ⁴₂He → ¹²₆C.
B¹²₆C + ⁴₂He → ¹⁶₈O.
C¹⁶₈O + ⁴₂He → ²⁰₁₀Ne.

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Nitrogen is +2 in NO and +4 in NO₂.
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