OCR A-Level Chemistry B H433
Development of Practical Skills in Chemistry
Elements of Life
Developing Fuels
Elements From the Sea
The Ozone Story
What's in a Medicine?
The Chemical Industry
Polymers and Life
Oceans
Developing Metals
Colour by Design
Chemical Literacy
Mathematical Skills in Chemistry
Elements of Life
Concentration, titration and writing balanced equations
- 2 things to know
- Components 01, 02 and 03
Overview
Recall questions on concentration and dilution, preparing a standard solution, titration technique and uncertainty, and writing balanced and ionic equations.
What you need to know
Answer each one before you reveal it.
A burette can be read to ±0.05 cm³. What is the uncertainty in a titre of 25.00 cm³, as an absolute value and as a percentage?
Questions from this subtopic
Each one with the model answer underneath.
- 1
How would you accurately measure out a mass of solid for a quantitative experiment?
Model answer
Weigh the solid in a container on a balance reading to at least two decimal places, tip it into the reaction vessel, then reweigh the empty container and take the difference, so that any solid left behind is not counted.
- 2
Calculate the concentration of a solution made by dissolving 5.85 g of sodium chloride in water and making the volume up to 250 cm³ (M(NaCl) = 58.5 g mol⁻¹).
Model answer
The amount of NaCl is 5.85 ÷ 58.5 = 0.100 mol in 0.250 dm³, so the concentration is 0.100 ÷ 0.250 = 0.400 mol dm⁻³.
- 3
25.0 cm³ of a 2.00 mol dm⁻³ solution is diluted with water to a total volume of 250 cm³. What is the new concentration?
Model answer
The amount of solute is unchanged at 0.0250 × 2.00 = 0.0500 mol, now in 0.250 dm³, so the concentration is 0.200 mol dm⁻³.
- 4
22.50 cm³ of 0.100 mol dm⁻³ hydrochloric acid exactly neutralises 25.0 cm³ of sodium hydroxide solution. Calculate the concentration of the alkali.
Model answer
The acid supplies 0.02250 × 0.100 = 2.25 × 10⁻³ mol of HCl, and the reaction is 1 : 1, so the alkali concentration is 2.25 × 10⁻³ ÷ 0.0250 = 0.0900 mol dm⁻³.
- 5
A student records titres of 24.10, 23.55, 23.45 and 23.50 cm³. Calculate the mean titre they should use.
Model answer
The 24.10 cm³ rough titre is an outlier and is discarded, leaving three concordant results whose mean is (23.55 + 23.45 + 23.50) ÷ 3 = 23.50 cm³.
- 6
A burette can be read to ±0.05 cm³. What is the uncertainty in a titre of 25.00 cm³, as an absolute value and as a percentage?
Model answer
Two readings are needed, so the absolute uncertainty is ±0.10 cm³, which is 0.10 ÷ 25.00 × 100 = 0.40% of the titre.
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