OCR A-Level Chemistry B H433
Development of Practical Skills in Chemistry
Elements of Life
Developing Fuels
Elements From the Sea
The Ozone Story
What's in a Medicine?
The Chemical Industry
Polymers and Life
Oceans
Developing Metals
Colour by Design
Chemical Literacy
Mathematical Skills in Chemistry
Elements From the Sea
Using the Kc expression to explain a shift in position
- 1 thing to know
- Components 01, 02 and 03
Overview
Recall questions on why adding a reactant or removing a product shifts the position while Kc stays fixed, and on the reaction quotient.
What you need to know
Answer each one before you reveal it.
Questions from this subtopic
Each one with the model answer underneath.
- 1
What happens to the position of equilibrium when more of a reactant is added?
Model answer
It moves to the right, forming more product.
- 2
Use the Kc expression to explain why adding a reactant shifts the equilibrium to the right.
Model answer
Raising a concentration term on the bottom would make the ratio smaller than Kc, so terms on the top must grow until the original value is restored.
- 3
What happens if a product is continually removed from an equilibrium mixture?
Model answer
The equilibrium keeps shifting to the right as the system replaces what has been taken away.
- 4
Explain, using the Kc expression, why removing a product shifts the equilibrium to the right.
Model answer
Taking away a term from the top drops the ratio below Kc, so more product must be made to bring it back up.
- 5
What must happen if a concentration term on the top of a Kc expression is increased?
Model answer
A term on the bottom must become larger as well so that the ratio still equals Kc, which means the equilibrium position moves to the left.
- 6
Why does the value of Kc stay the same while these shifts are taking place?
Model answer
The temperature has not changed, and temperature is the only thing that alters the value of the constant.
Other ways to work this
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