OCR A-Level Chemistry B H433
Development of Practical Skills in Chemistry
Elements of Life
Developing Fuels
Elements From the Sea
The Ozone Story
What's in a Medicine?
The Chemical Industry
Polymers and Life
Oceans
Developing Metals
Colour by Design
Chemical Literacy
Mathematical Skills in Chemistry
Oceans
Predicting precipitation and the common ion effect
- 2 things to know
- Components 01, 02 and 03
Overview
Recall questions on comparing the ionic product with Ksp, halving concentrations on mixing, and why a common ion reduces solubility.
What you need to know
Answer each one before you reveal it.
How does a fall in ocean pH threaten shells made of calcium carbonate?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Ksp for calcium carbonate is 5.0 × 10⁻⁹ mol² dm⁻⁶. Calculate its solubility in mol dm⁻³ and in g dm⁻³, given Mᵣ = 100.1.
Model answer
s = √(5.0 × 10⁻⁹) = 7.1 × 10⁻⁵ mol dm⁻³, which is 7.1 × 10⁻⁵ × 100.1 = 7.1 × 10⁻³ g dm⁻³.
- 2
Equal volumes of 2.0 × 10⁻³ mol dm⁻³ silver nitrate and 2.0 × 10⁻³ mol dm⁻³ sodium chloride are mixed. Will silver chloride precipitate, given Ksp = 1.7 × 10⁻¹⁰ mol² dm⁻⁶?
Model answer
After mixing each ion is at 1.0 × 10⁻³ mol dm⁻³, giving an ionic product of 1.0 × 10⁻⁶ mol² dm⁻⁶, which exceeds Ksp, so a precipitate forms.
- 3
Why must the concentrations be halved when equal volumes of two solutions are mixed?
Model answer
Each solution is diluted into twice its original volume, so the amount of each ion is spread through double the volume.
- 4
What does it mean if the ionic product of a mixture is smaller than Ksp?
Model answer
The solution is unsaturated, so no precipitate forms and any solid present would dissolve.
- 5
Calculate the solubility of silver chloride in 0.10 mol dm⁻³ sodium chloride, given Ksp = 1.7 × 10⁻¹⁰ mol² dm⁻⁶.
Model answer
[Ag⁺] = Ksp/[Cl⁻] = 1.7 × 10⁻¹⁰/0.10 = 1.7 × 10⁻⁹ mol dm⁻³, far below the value of 1.3 × 10⁻⁵ mol dm⁻³ in pure water.
- 6
Why does adding a common ion reduce the solubility of a sparingly soluble salt?
Model answer
Increasing the concentration of one ion shifts the dissolving equilibrium back towards the solid so that the product of the ion concentrations still equals Ksp.
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