OCR A-Level Chemistry B H433
Development of Practical Skills in Chemistry
Elements of Life
Developing Fuels
Elements From the Sea
The Ozone Story
What's in a Medicine?
The Chemical Industry
Polymers and Life
Oceans
Developing Metals
Colour by Design
Chemical Literacy
Mathematical Skills in Chemistry
What's in a Medicine?
Identifying a compound from its fragments and the M+1 peak
- 2 things to know
- Components 01, 02 and 03
Overview
Recall questions on the common fragment masses, working a structure out from a spectrum, and what causes the M+1 peak.
What you need to know
Answer each one before you reveal it.
In the aspirin spectrum a peak at m/z 120 follows the one at 138. What neutral molecule has been lost?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What fragment ion gives a peak at m/z 15, and what is its formula?
Model answer
The methyl cation, CH₃⁺, gives a peak at m/z 15.
- 2
Identify the fragment ion responsible for a peak at m/z 29 in an alkane spectrum.
Model answer
It is the ethyl cation, C₂H₅⁺.
- 3
A ketone gives peaks at m/z 58 and m/z 43. Identify the compound and the fragment lost.
Model answer
The compound is propanone, CH₃COCH₃, and a methyl group of mass 15 has been lost to leave CH₃CO⁺ at 43.
- 4
Ethanol gives peaks at m/z 46, 31 and 15. Identify the species giving the peak at 31.
Model answer
Loss of a methyl group from the molecular ion leaves CH₂OH⁺, of mass 31.
- 5
What mass difference between the molecular ion and a fragment peak indicates the loss of a methyl group?
Model answer
A difference of 15.
- 6
Ethanoic acid gives an M⁺ peak at m/z 60 and a strong peak at m/z 45. What has been lost?
Model answer
A methyl group of mass 15 has been lost, since 60 − 15 = 45.
Other ways to work this
The same content, four other ways.
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