OCR A-Level Chemistry B H433
Development of Practical Skills in Chemistry
Elements of Life
Developing Fuels
Elements From the Sea
The Ozone Story
What's in a Medicine?
The Chemical Industry
Polymers and Life
Oceans
Developing Metals
Colour by Design
Chemical Literacy
Mathematical Skills in Chemistry
The Ozone Story
Initiation, propagation and termination in a radical chain reaction
- 2 things to know
- Components 01, 02 and 03
Overview
Recall questions on the three stages, why ultraviolet light is needed, and why the reaction gives a mixture of products.
What you need to know
Answer each one before you reveal it.
Why is the radical substitution of methane by chlorine of little use for preparing a pure haloalkane?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Name the three stages of a radical chain reaction.
Model answer
Initiation, propagation and termination.
- 2
What happens during initiation?
Model answer
Radicals are created for the first time, usually by the homolysis of a bond under ultraviolet light.
- 3
Write the initiation equation for the reaction of methane with chlorine.
Model answer
Cl₂ → 2•Cl, brought about by ultraviolet light.
- 4
Why is the Cl–Cl bond broken in initiation rather than a C–H bond?
Model answer
The Cl–Cl bond is far weaker, at 242 kJ mol⁻¹ against 413 kJ mol⁻¹ for C–H, so it breaks with the lower-energy photons available.
- 5
Write the two propagation steps for methane and chlorine.
Model answer
•Cl + CH₄ → •CH₃ + HCl, then •CH₃ + Cl₂ → CH₃Cl + •Cl.
- 6
What is characteristic of a propagation step?
Model answer
A radical is used up and a new radical is made, so the number of radicals stays the same and the chain keeps going.
Other ways to work this
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