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Acid-Base Equilibria

Buffer calculations

  • 3 things to know
  • Component 1

Overview

Recall questions on the buffer expression and why it uses the ratio of acid to salt, calculating the pH of a buffer from stated amounts, working from an acid partly neutralised by alkali, finding the ratio needed for a target pH, and the effect of adding a small amount of acid or alkali.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Key term

State the expression used to find the hydrogen ion concentration of an acidic buffer.

Key term

State the logarithmic form of the expression used for buffer calculations.

Key term

Explain why the volume of the solution cancels out of a buffer calculation.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the expression used to find the hydrogen ion concentration of an acidic buffer.

    Model answer

    [H⁺] = Ka × [acid] ÷ [salt].

  2. 2

    State the logarithmic form of the expression used for buffer calculations.

    Model answer

    pH = pKa + log([salt] ÷ [acid]).

  3. 3

    What is the pH of a buffer in which the concentrations of the acid and its salt are equal?

    Model answer

    It is equal to the pKa of the acid.

  4. 4

    Calculate the pH of a buffer that is 0.100 mol dm⁻³ in ethanoic acid and 0.150 mol dm⁻³ in sodium ethanoate, given Ka = 1.75 × 10⁻⁵ mol dm⁻³.

    Model answer

    [H⁺] = 1.75 × 10⁻⁵ × (0.100 ÷ 0.150) = 1.17 × 10⁻⁵ mol dm⁻³, so the pH is 4.93.

  5. 5

    Calculate the pH of a buffer that is 0.200 mol dm⁻³ in ethanoic acid and 0.100 mol dm⁻³ in sodium ethanoate, given Ka = 1.75 × 10⁻⁵ mol dm⁻³.

    Model answer

    [H⁺] = 1.75 × 10⁻⁵ × 2.00 = 3.50 × 10⁻⁵ mol dm⁻³, so the pH is 4.46.

  6. 6

    Calculate the ratio of salt to acid needed to make a buffer of pH 5.00 from ethanoic acid, given Ka = 1.75 × 10⁻⁵ mol dm⁻³.

    Model answer

    [H⁺] must be 1.00 × 10⁻⁵ mol dm⁻³, so the ratio of salt to acid is 1.75 × 10⁻⁵ ÷ 1.00 × 10⁻⁵ = 1.75.

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