Eduqas A-Level Chemistry A410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Specified Practical Work
Practical Skills and Techniques
Mathematical Skills in Chemistry
Mathematical Skills in Chemistry
Logarithms, pH and pKa
- 3 things to know
- Component 3
Overview
Recall questions on what a logarithm is and the relationship between a number and its logarithm, converting between hydrogen ion concentration and pH in both directions, between Ka and pKa, why a change of one pH unit is a factor of ten, and worked conversions.
What you need to know
Answer each one before you reveal it.
Why is acidity expressed on a logarithmic scale rather than as a concentration?
Calculate the pH of a solution in which the hydrogen ion concentration is 0.0200 mol dm⁻³.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Why is acidity expressed on a logarithmic scale rather than as a concentration?
Model answer
Hydrogen ion concentrations in ordinary solutions span more than fourteen orders of magnitude, from about 1 to 10⁻¹⁴ mol dm⁻³, and taking the negative logarithm compresses that enormous range onto a scale of small numbers that can be compared at a glance.
- 2
Calculate the pH of a solution in which the hydrogen ion concentration is 0.0200 mol dm⁻³.
Model answer
The pH is −log(2.00 × 10⁻²), which is 1.70.
- 3
A solution has a pH of 5.80. Calculate its hydrogen ion concentration and give the answer to two significant figures.
Model answer
[H⁺] is 10 raised to the power −5.80, which is 1.6 × 10⁻⁶ mol dm⁻³. Taking the negative logarithm of that value returns 5.80, which confirms it.
- 4
Calculate the pH of 0.0500 mol dm⁻³ sodium hydroxide solution at 298 K, taking Kw as 1.00 × 10⁻¹⁴ mol² dm⁻⁶.
Model answer
Dividing Kw by the hydroxide ion concentration gives [H⁺] = 1.00 × 10⁻¹⁴ ÷ 0.0500 = 2.00 × 10⁻¹³ mol dm⁻³, so the pH is 12.70.
- 5
An acid has Ka = 1.8 × 10⁻⁵ mol dm⁻³. Calculate its pKa.
Model answer
Taking the negative logarithm gives pKa = −log(1.8 × 10⁻⁵) = 4.74.
- 6
An acid has a pKa of 3.75. Calculate its acid dissociation constant.
Model answer
Taking the inverse logarithm gives Ka = 10⁻³·⁷⁵ = 1.78 × 10⁻⁴ mol dm⁻³.
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