Eduqas A-Level Chemistry A410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Specified Practical Work
Practical Skills and Techniques
Mathematical Skills in Chemistry
Equilibrium Constants
Calculating Kc and the amounts present at equilibrium
- 3 things to know
- Component 1
Overview
Recall questions on the initial, change and equilibrium layout, why the changes follow the balancing numbers, converting moles to concentrations and when the volume cancels, worked calculations of Kc from initial amounts, and working back from Kc to an equilibrium amount.
What you need to know
Answer each one before you reveal it.
Which three quantities are tabulated for each species when Kc is worked out from initial amounts?
Why must amounts in moles be converted into concentrations before being used in a Kc expression?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Which three quantities are tabulated for each species when Kc is worked out from initial amounts?
Model answer
The initial amount, the change that occurs as equilibrium is reached, and the amount present at equilibrium.
- 2
Why must amounts in moles be converted into concentrations before being used in a Kc expression?
Model answer
Kc is defined in terms of concentrations, so every amount must first be divided by the volume of the container.
- 3
When can the volume be left out of a Kc calculation?
Model answer
When the total number of moles is the same on both sides of the equation, because the volume terms then cancel.
- 4
One mole of ethanoic acid is mixed with one mole of ethanol and 0.333 mol of the acid remains at equilibrium. Calculate Kc for the esterification.
Model answer
0.667 mol of ester and of water have formed and 0.333 mol of ethanol is left, so Kc = (0.667 × 0.667) ÷ (0.333 × 0.333) = 4.01, with no units.
- 5
One mole of hydrogen and one mole of iodine are placed in a 1.00 dm³ vessel and 1.56 mol of hydrogen iodide is present at equilibrium. Calculate Kc.
Model answer
0.78 mol of each reactant has been used, leaving 0.22 mol dm⁻³ of each, so Kc = 1.56² ÷ (0.22 × 0.22) = 50.3, with no units.
- 6
Two moles of phosphorus(V) chloride are placed in a 2.00 dm³ vessel and 0.50 mol remains at equilibrium as it dissociates into PCl₃ and Cl₂. Calculate Kc.
Model answer
1.50 mol of each product has formed, so the concentrations are 0.25, 0.75 and 0.75 mol dm⁻³, giving Kc = (0.75 × 0.75) ÷ 0.25 = 2.25 mol dm⁻³.
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