Eduqas A-Level Chemistry A410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Specified Practical Work
Practical Skills and Techniques
Mathematical Skills in Chemistry
Mathematical Skills in Chemistry
Exponentials, the Arrhenius equation and rate
- 3 things to know
- Component 3
Overview
Recall questions on the exponential form of the Arrhenius equation and its logarithmic form, what is plotted to obtain a straight line, what the gradient and intercept give, calculating an activation energy from two rate constants, and why a small temperature rise changes the rate so much.
What you need to know
Answer each one before you reveal it.
A first-order reaction has a rate constant of 2.50 × 10⁻³ s⁻¹ and starts at 0.800 mol dm⁻³. Calculate the concentration remaining after 300 s.
Explain why the half-life of a first-order reaction does not depend on the starting concentration.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the Arrhenius equation and explain what each symbol stands for.
Model answer
The equation is k = A exp(−Ea/RT), in which k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant and T is the absolute temperature.
- 2
Why does the exponential term make the rate of a reaction so sensitive to temperature?
Model answer
The temperature appears in the denominator of an exponent, so a small change in T produces a proportionally much larger change in the value of the exponential, and it is that factor which multiplies the rate constant.
- 3
Calculate the value of the exponential factor for a reaction of activation energy 50.0 kJ mol⁻¹ at 298 K.
Model answer
The exponent is −50 000 ÷ (8.314 × 298) = −20.18, and exp(−20.18) is 1.7 × 10⁻⁹, a pure number with no units.
- 4
Show by calculation what happens to the rate constant of a reaction of activation energy 50.0 kJ mol⁻¹ when the temperature rises from 298 K to 308 K.
Model answer
The ratio of the two rate constants is exp[(Ea/R)(1/298 − 1/308)] = exp(6014 × 1.09 × 10⁻⁴) = exp(0.655) = 1.9, so the rate constant very nearly doubles for a rise of ten kelvin.
- 5
What does the exponential term in the Arrhenius equation represent physically?
Model answer
It is the fraction of the colliding molecules that possess at least the activation energy, so it measures how many collisions have enough energy to lead to reaction.
- 6
A first-order reaction has a rate constant of 2.50 × 10⁻³ s⁻¹ and starts at 0.800 mol dm⁻³. Calculate the concentration remaining after 300 s.
Model answer
The concentration follows [A] = [A]₀ exp(−kt), and kt is 0.750, so [A] = 0.800 × exp(−0.750) = 0.800 × 0.472 = 0.378 mol dm⁻³.
Other ways to work this
The same content, four other ways.
What is inside Levo
Six ways to work the same material.
Every question in Mathematical Skills in Chemistry, on a schedule.
Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.
Or £46 a year, about £3.83 a month. Cancel anytime.