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Mathematical Skills in Chemistry

Exponentials, the Arrhenius equation and rate

  • 3 things to know
  • Component 3

Overview

Recall questions on the exponential form of the Arrhenius equation and its logarithmic form, what is plotted to obtain a straight line, what the gradient and intercept give, calculating an activation energy from two rate constants, and why a small temperature rise changes the rate so much.

What you need to know

Answer each one before you reveal it.

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Key term

State the Arrhenius equation and explain what each symbol stands for.

Numbers

A first-order reaction has a rate constant of 2.50 × 10⁻³ s⁻¹ and starts at 0.800 mol dm⁻³. Calculate the concentration remaining after 300 s.

Key term

Explain why the half-life of a first-order reaction does not depend on the starting concentration.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the Arrhenius equation and explain what each symbol stands for.

    Model answer

    The equation is k = A exp(−Ea/RT), in which k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant and T is the absolute temperature.

  2. 2

    Why does the exponential term make the rate of a reaction so sensitive to temperature?

    Model answer

    The temperature appears in the denominator of an exponent, so a small change in T produces a proportionally much larger change in the value of the exponential, and it is that factor which multiplies the rate constant.

  3. 3

    Calculate the value of the exponential factor for a reaction of activation energy 50.0 kJ mol⁻¹ at 298 K.

    Model answer

    The exponent is −50 000 ÷ (8.314 × 298) = −20.18, and exp(−20.18) is 1.7 × 10⁻⁹, a pure number with no units.

  4. 4

    Show by calculation what happens to the rate constant of a reaction of activation energy 50.0 kJ mol⁻¹ when the temperature rises from 298 K to 308 K.

    Model answer

    The ratio of the two rate constants is exp[(Ea/R)(1/298 − 1/308)] = exp(6014 × 1.09 × 10⁻⁴) = exp(0.655) = 1.9, so the rate constant very nearly doubles for a rise of ten kelvin.

  5. 5

    What does the exponential term in the Arrhenius equation represent physically?

    Model answer

    It is the fraction of the colliding molecules that possess at least the activation energy, so it measures how many collisions have enough energy to lead to reaction.

  6. 6

    A first-order reaction has a rate constant of 2.50 × 10⁻³ s⁻¹ and starts at 0.800 mol dm⁻³. Calculate the concentration remaining after 300 s.

    Model answer

    The concentration follows [A] = [A]₀ exp(−kt), and kt is 0.750, so [A] = 0.800 × exp(−0.750) = 0.800 × 0.472 = 0.378 mol dm⁻³.

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AThe equation is k = A exp(−Ea/RT).
BHere k is the rate constant.
CA is the pre-exponential factor.

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Kc is a fixed number at a given temperature.
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