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Simple Equilibria and Acid-Base Reactions

Le Chatelier's principle

  • 3 things to know
  • Components 1 and 2

Overview

Recall questions on the statement of the principle, the effect of changing concentration, pressure and temperature on the position of equilibrium, why a catalyst changes nothing, and the compromise conditions chosen for a named industrial process.

What you need to know

Answer each one before you reveal it.

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Key term

State Le Chatelier's principle.

Key term

The oxidation 2SO₂(g) + O₂(g) ⇌ 2SO₃(g) is exothermic. Predict and explain the effect of raising the temperature on the yield of sulfur trioxide.

Key term

What happens to the position of the equilibrium CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂O when extra ethanol is added?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State Le Chatelier's principle.

    Model answer

    When a change is imposed on a system at equilibrium, the position of equilibrium shifts in the direction that opposes that change.

  2. 2

    The oxidation 2SO₂(g) + O₂(g) ⇌ 2SO₃(g) is exothermic. Predict and explain the effect of raising the temperature on the yield of sulfur trioxide.

    Model answer

    The equilibrium shifts to the left, towards the endothermic direction, in order to absorb the added heat, so the yield of SO₃ falls.

  3. 3

    Predict the effect of increasing the total pressure on the equilibrium N₂(g) + 3H₂(g) ⇌ 2NH₃(g).

    Model answer

    There are four moles of gas on the left and two on the right, so the equilibrium shifts to the right to reduce the number of gas molecules and the yield of ammonia rises.

  4. 4

    Why does a change of pressure have no effect on the position of the equilibrium H₂(g) + I₂(g) ⇌ 2HI(g)?

    Model answer

    There are two moles of gas on each side, so shifting in either direction would not change the number of gas molecules and neither direction is favoured.

  5. 5

    What happens to the position of the equilibrium CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂O when extra ethanol is added?

    Model answer

    The equilibrium shifts to the right to remove the added ethanol, so more ester is formed.

  6. 6

    Explain how continuously removing a product can drive a reversible reaction almost to completion.

    Model answer

    Removing a product lowers its concentration, so the equilibrium repeatedly shifts to the right to replace it and the reaction is pushed further towards the products.

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