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The Periodic Table

Reactivity of Group 1 and Group 2 metals

  • 3 things to know
  • Components 1 and 2

Overview

Recall questions on the reactions of the Group 1 and Group 2 metals with oxygen, water and dilute acid, the trend in vigour down each group and its explanation through falling ionisation energy, comparing the two groups, and the equations for the named reactions.

What you need to know

Answer each one before you reveal it.

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Key term

How does reactivity change down Group 1?

Key term

Explain the reactivity trend down Group 1.

Key term

Compare the reactivity of a Group 1 metal with the Group 2 metal in the same period.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    How does reactivity change down Group 1?

    Model answer

    Reactivity increases steadily from lithium to caesium.

  2. 2

    Explain the reactivity trend down Group 1.

    Model answer

    The outer electron lies further from the nucleus and is shielded by more inner shells, so the first ionisation energy falls and the electron is given up more easily.

  3. 3

    How does reactivity change down Group 2, and why?

    Model answer

    Reactivity increases down the group, because the sum of the first two ionisation energies falls as the outer electrons get further from the nucleus and better shielded.

  4. 4

    Compare the reactivity of a Group 1 metal with the Group 2 metal in the same period.

    Model answer

    The Group 1 metal is the more reactive, because it needs to lose only one electron, whereas the Group 2 metal must also supply the much larger second ionisation energy.

  5. 5

    Why is the reactivity of these metals essentially a measure of how easily they are oxidised?

    Model answer

    Every characteristic reaction of an s-block metal involves losing its outer electrons to form a positive ion, so the ease of that loss fixes how reactive the metal is.

  6. 6

    Nuclear charge increases down a group, so why does reactivity not fall?

    Model answer

    The extra distance of the outer electron from the nucleus and the extra shielding from each new inner shell together outweigh the increase in nuclear charge.

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