Eduqas A-Level Chemistry A410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Specified Practical Work
Practical Skills and Techniques
Mathematical Skills in Chemistry
Mathematical Skills in Chemistry
Tangents and rates of change
- 3 things to know
- Component 3
Overview
Recall questions on constructing a tangent to a curve and taking its gradient, obtaining an instantaneous rate from a concentration–time graph, why the initial rate is measured at time zero, comparing gradients at different times, and what a levelling curve indicates.
What you need to know
Answer each one before you reveal it.
Why is the gradient of a tangent negative for a reactant and positive for a product?
A tangent at the origin of a concentration against time curve falls from 0.600 mol dm⁻³ to zero at 250 s. Calculate the initial rate.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Why is a tangent needed to find the rate from a curved concentration against time graph?
Model answer
The gradient of a curve is different at every point, so a single straight line drawn to touch the curve at one point is the only way to express the rate of change at that particular moment.
- 2
What does the gradient of the tangent to a concentration against time curve represent, and what are its units?
Model answer
It gives the rate of the reaction at that instant, in mol dm⁻³ s⁻¹, since the change in concentration is divided by the change in time.
- 3
Where must a tangent touch the curve if the initial rate is wanted?
Model answer
It must touch the curve at the point where time is zero, so the gradient corresponds to the moment of mixing when the concentrations are still those that were measured out.
- 4
A tangent at the origin of a concentration against time curve falls from 0.600 mol dm⁻³ to zero at 250 s. Calculate the initial rate.
Model answer
The gradient is 0.600 ÷ 250 = 2.40 × 10⁻³, so the initial rate is 2.40 × 10⁻³ mol dm⁻³ s⁻¹.
- 5
The tangent to a gas volume against time curve has a gradient of 12.0 cm³ s⁻¹. Convert this to a rate in mol s⁻¹ using a molar gas volume of 24.0 dm³ mol⁻¹.
Model answer
One mole occupies 24 500 cm³ at room temperature and pressure, so the rate is 12.0 ÷ 24 500 = 4.90 × 10⁻⁴ mol s⁻¹.
- 6
Why is the initial rate the most reliable rate to take from a curve?
Model answer
At the moment of mixing the concentrations of every reactant are known exactly from the volumes and concentrations measured out, and no product has yet accumulated to interfere or to drive a back reaction.
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