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Rates of Reaction

Collision theory and the conditions that change rate

  • 3 things to know
  • Components 1 and 2

Overview

Rate of a chemical reaction and successful collision.

What you need to know

Answer each one before you reveal it.

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Key term

State the two requirements of collision theory for a collision to lead to reaction.

Key term

Explain in terms of collisions why increasing the pressure of a gaseous reaction mixture speeds it up.

Key term

Give the two separate reasons why raising the temperature increases the rate of a reaction.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the two requirements of collision theory for a collision to lead to reaction.

    Model answer

    The colliding particles must meet with at least the activation energy, and they must be correctly oriented with respect to each other.

  2. 2

    What is meant by the rate of a chemical reaction?

    Model answer

    It is the change in the amount or concentration of a reactant or product in a given time.

  3. 3

    Explain in terms of collisions why increasing the concentration of a solution speeds up a reaction.

    Model answer

    There are more reactant particles in each unit of volume, so collisions happen more often and more of them succeed in a given time.

  4. 4

    Explain in terms of collisions why increasing the pressure of a gaseous reaction mixture speeds it up.

    Model answer

    The same number of molecules is squeezed into a smaller volume, so the molecules are closer together and collide more frequently.

  5. 5

    Explain why powdering a solid reactant increases the rate of its reaction with an acid.

    Model answer

    Powdering exposes a much greater surface area, so more of the solid is available for the acid particles to collide with at any moment.

  6. 6

    Give the two separate reasons why raising the temperature increases the rate of a reaction.

    Model answer

    The particles move faster so they collide more often, and a much larger fraction of them has energy equal to or greater than the activation energy.

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AThe equation is k = A exp(−Ea/RT).
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Kc is a fixed number at a given temperature.
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