Eduqas A-Level Chemistry A410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Specified Practical Work
Practical Skills and Techniques
Mathematical Skills in Chemistry
Redox Reactions
Redox titration calculations
- 3 things to know
- Component 1
Overview
Recall questions on the manganate(VII) and dichromate(VI) half-equations, combining them with the reducing agent to give the reaction ratio, the mole calculation from the titre, expressing the result as a concentration or a percentage purity, and checking the answer against the titre.
What you need to know
Answer each one before you reveal it.
A 25.0 cm³ portion of an iron(II) solution needs 22.5 cm³ of 0.0200 mol dm⁻³ potassium manganate(VII). Calculate the concentration of the iron(II) solution.
Calculate the volume of 0.0200 mol dm⁻³ potassium manganate(VII) needed to react with 20.0 cm³ of 0.0250 mol dm⁻³ sodium ethanedioate.
Questions from this subtopic
Each one with the model answer underneath.
- 1
A 25.0 cm³ portion of an iron(II) solution needs 22.5 cm³ of 0.0200 mol dm⁻³ potassium manganate(VII). Calculate the concentration of the iron(II) solution.
Model answer
The titre contains 4.50 × 10⁻⁴ mol of MnO₄⁻, which reacts with 2.25 × 10⁻³ mol of Fe²⁺, giving a concentration of 0.0900 mol dm⁻³.
- 2
A 25.0 cm³ portion of a copper(II) solution liberates iodine that needs 24.0 cm³ of 0.100 mol dm⁻³ sodium thiosulfate. Calculate the concentration of the copper(II) ions.
Model answer
The titre contains 2.40 × 10⁻³ mol of thiosulfate, which corresponds to 2.40 × 10⁻³ mol of Cu²⁺, so the concentration is 0.0960 mol dm⁻³.
- 3
A 1.00 g sample of brass is dissolved, made up to 250 cm³, and 25.0 cm³ portions each need 22.0 cm³ of 0.0500 mol dm⁻³ sodium thiosulfate. Calculate the percentage of copper in the brass, taking Ar(Cu) as 63.5.
Model answer
Each portion holds 1.10 × 10⁻³ mol of copper, so the whole sample holds 1.10 × 10⁻² mol, a mass of 0.699 g, which is 69.9% copper.
- 4
A 0.400 g sample of an iron ore is dissolved and all the iron reduced to iron(II); the solution needs 24.0 cm³ of 0.0200 mol dm⁻³ manganate(VII). Calculate the percentage of iron in the ore, taking Ar(Fe) as 55.8.
Model answer
The titre contains 4.80 × 10⁻⁴ mol of MnO₄⁻, so the sample holds 2.40 × 10⁻³ mol of iron, a mass of 0.134 g, which is 33.5% iron.
- 5
Calculate the volume of 0.0200 mol dm⁻³ potassium manganate(VII) needed to react with 20.0 cm³ of 0.0250 mol dm⁻³ sodium ethanedioate.
Model answer
The ethanedioate is 5.00 × 10⁻⁴ mol, which needs two fifths of that amount of MnO₄⁻, namely 2.00 × 10⁻⁴ mol, requiring 10.0 cm³.
- 6
A sample of impure iron(II) sulfate is dissolved in dilute sulfuric acid and needs 18.0 cm³ of 0.0200 mol dm⁻³ manganate(VII). Calculate the mass of FeSO₄ in the sample, taking its Mr as 152.
Model answer
The titre contains 3.60 × 10⁻⁴ mol of MnO₄⁻, so 1.80 × 10⁻³ mol of iron(II) is present, a mass of 0.274 g of FeSO₄.
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