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Redox Reactions

Redox titration calculations

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Overview

Recall questions on the manganate(VII) and dichromate(VI) half-equations, combining them with the reducing agent to give the reaction ratio, the mole calculation from the titre, expressing the result as a concentration or a percentage purity, and checking the answer against the titre.

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Numbers

Calculate the amount of iron(II) ions oxidised by 25.0 cm³ of 0.100 mol dm⁻³ potassium dichromate(VI).

Numbers

A 25.0 cm³ portion of an iron(II) solution needs 22.5 cm³ of 0.0200 mol dm⁻³ potassium manganate(VII). Calculate the concentration of the iron(II) solution.

Numbers

Calculate the volume of 0.0200 mol dm⁻³ potassium manganate(VII) needed to react with 20.0 cm³ of 0.0250 mol dm⁻³ sodium ethanedioate.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    A 25.0 cm³ portion of an iron(II) solution needs 22.5 cm³ of 0.0200 mol dm⁻³ potassium manganate(VII). Calculate the concentration of the iron(II) solution.

    Model answer

    The titre contains 4.50 × 10⁻⁴ mol of MnO₄⁻, which reacts with 2.25 × 10⁻³ mol of Fe²⁺, giving a concentration of 0.0900 mol dm⁻³.

  2. 2

    A 25.0 cm³ portion of a copper(II) solution liberates iodine that needs 24.0 cm³ of 0.100 mol dm⁻³ sodium thiosulfate. Calculate the concentration of the copper(II) ions.

    Model answer

    The titre contains 2.40 × 10⁻³ mol of thiosulfate, which corresponds to 2.40 × 10⁻³ mol of Cu²⁺, so the concentration is 0.0960 mol dm⁻³.

  3. 3

    A 1.00 g sample of brass is dissolved, made up to 250 cm³, and 25.0 cm³ portions each need 22.0 cm³ of 0.0500 mol dm⁻³ sodium thiosulfate. Calculate the percentage of copper in the brass, taking Ar(Cu) as 63.5.

    Model answer

    Each portion holds 1.10 × 10⁻³ mol of copper, so the whole sample holds 1.10 × 10⁻² mol, a mass of 0.699 g, which is 69.9% copper.

  4. 4

    A 0.400 g sample of an iron ore is dissolved and all the iron reduced to iron(II); the solution needs 24.0 cm³ of 0.0200 mol dm⁻³ manganate(VII). Calculate the percentage of iron in the ore, taking Ar(Fe) as 55.8.

    Model answer

    The titre contains 4.80 × 10⁻⁴ mol of MnO₄⁻, so the sample holds 2.40 × 10⁻³ mol of iron, a mass of 0.134 g, which is 33.5% iron.

  5. 5

    Calculate the volume of 0.0200 mol dm⁻³ potassium manganate(VII) needed to react with 20.0 cm³ of 0.0250 mol dm⁻³ sodium ethanedioate.

    Model answer

    The ethanedioate is 5.00 × 10⁻⁴ mol, which needs two fifths of that amount of MnO₄⁻, namely 2.00 × 10⁻⁴ mol, requiring 10.0 cm³.

  6. 6

    A sample of impure iron(II) sulfate is dissolved in dilute sulfuric acid and needs 18.0 cm³ of 0.0200 mol dm⁻³ manganate(VII). Calculate the mass of FeSO₄ in the sample, taking its Mr as 152.

    Model answer

    The titre contains 3.60 × 10⁻⁴ mol of MnO₄⁻, so 1.80 × 10⁻³ mol of iron(II) is present, a mass of 0.274 g of FeSO₄.

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