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Redox Reactions

The reaction of Cu²⁺ with iodide ions

  • 3 things to know
  • Component 1

Overview

Recall questions on the equation and the observations, why copper(II) is reduced to copper(I) iodide, the iodine released and the starch test for it, why the mixture is titrated against thiosulfate, and the calculation of the copper content from the titre.

What you need to know

Answer each one before you reveal it.

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Key term

Write the equation for the reaction between copper(II) ions and an excess of iodide ions.

Key term

Which species is reduced when copper(II) ions react with iodide ions?

Key term

Which species is oxidised when copper(II) ions react with iodide ions?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Write the equation for the reaction between copper(II) ions and an excess of iodide ions.

    Model answer

    2Cu²⁺(aq) + 4I⁻(aq) → 2CuI(s) + I₂(aq).

  2. 2

    Which species is reduced when copper(II) ions react with iodide ions?

    Model answer

    Copper(II) is reduced to copper(I), which is precipitated as copper(I) iodide.

  3. 3

    Which species is oxidised when copper(II) ions react with iodide ions?

    Model answer

    Half of the iodide ions are oxidised to iodine.

  4. 4

    Describe what is seen when excess potassium iodide solution is added to copper(II) sulfate solution.

    Model answer

    A brown colour appears in the solution from the liberated iodine, and an off-white precipitate of copper(I) iodide is suspended in it.

  5. 5

    Why must the potassium iodide be added in excess?

    Model answer

    An excess makes certain every copper(II) ion reacts, so the iodine liberated measures all the copper present.

  6. 6

    Which standard solution is used to determine the iodine liberated by copper(II) ions?

    Model answer

    Standard sodium thiosulfate solution is used.

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