Eduqas A-Level Chemistry A410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Specified Practical Work
Practical Skills and Techniques
Mathematical Skills in Chemistry
Carboxylic Acids and Their Derivatives
Hydroxynitriles, hydrolysis and reduction of nitriles
- 3 things to know
- Component 2
Overview
Reagents used to convert an aldehyde into a hydroxynitrile, product formed when ethanal reacts with hydrogen cyanide and product formed when propanone reacts with hydrogen cyanide.
What you need to know
Answer each one before you reveal it.
Name the product formed when ethanal reacts with hydrogen cyanide.
Name the product formed when propanone reacts with hydrogen cyanide.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the reagents used to convert an aldehyde into a hydroxynitrile.
Model answer
Potassium cyanide with dilute sulfuric acid is used, so that hydrogen cyanide is generated in the mixture together with a supply of cyanide ions.
- 2
Name the product formed when ethanal reacts with hydrogen cyanide.
Model answer
The product is 2-hydroxypropanenitrile.
- 3
Name the product formed when propanone reacts with hydrogen cyanide.
Model answer
The product is 2-hydroxy-2-methylpropanenitrile.
- 4
Explain why the hydroxynitrile obtained from ethanal is optically inactive.
Model answer
The carbonyl group is flat, so the cyanide ion is equally likely to attack either face, and the two enantiomers are produced in equal amounts as a racemic mixture whose rotations cancel.
- 5
Explain why the hydroxynitrile obtained from propanone has no chiral centre.
Model answer
The central carbon carries two identical methyl groups, so it does not have four different groups attached.
- 6
Explain why a trace of alkali or of a cyanide salt is needed rather than hydrogen cyanide alone.
Model answer
Hydrogen cyanide is a weak acid and dissociates very little, so on its own it provides too few of the cyanide ions that act as the attacking nucleophile.
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